Rcsc(theta) = 3
r/sin(theta) = 3
r =3sin(theta)

Now use the relation between polar coordinates and rectangular coordinates

x = rcos(theta)
y = r sin(theta)

=> x = [3sin(theta)]cos(theta)
x = 3 sin(theta)cos(theta)

and y = [3sin(theta)]sin(theta)
y = 3 [sin(theta)]^2

4 0

2 years ago

A basketball player's hang time is the time spent in the air when shooting a basket. The formula <img src="https://tex.z-dn.net

Crank

As with any problem involving formulas, fill in the information you have and solve for the remaining variable.
.. 1.09 = $\frac{ \sqrt{d}}{2}$
.. $(2 \times 1.09)^{2} = d$
.. d ≈ 4.8 . . . . feet

7 0

2 years ago

Read 2 more answers

Which of the following are the roots of the equation:

Rasek [7]

The answer is most definitely D :)

8 0

2 years ago