Answer:
The number of six non conforming transducers at most =54/60=0.9
The number of fewer than six non conforming transducers =51/60=0.85
The number of at least six non conforming transducers at most =30/60=0.5
d) The center of the histogram is around 2 or 3 and it shows that there is some positive skewness in the data
Step-by-step explanation:
Relative Frequency	Frequency       x
6/60=0.1                            6                   0
0.2                                    12                    1
0.2                                   12                     2
0.25                            15                      3
0.1                                    6                       4
0.05                               3                 5
0.05                               3                 6
0.0167                              1                          7
<u>0.033                               2                  8</u>
<u>∑                                    60                   </u>
The number of six non conforming transducers at most
= 6+12+12+15+6+3= 54
The number of six non conforming transducers at most =54/60=0.9
The number of fewer than five non conforming transducers 
= 6+12+12+15+6 = 51
The number of fewer than six non conforming transducers =51/60=0.85
  
The number of at least six non conforming transducers 
2+1+3+3+6+15= 30
The number of at least six non conforming transducers at most =30/60=0.5
We plot the histogram by placing the percentages (or relative frequency *100) on the y –axis and the X on the x-axis.
The center of the histogram is given by the mean of the distribution which in this case is = ∑fx/∑f= 161/60= 2.683
So option d is the best answer
d) The center of the histogram is around 2 or 3 and it shows that there is some positive skewness in the data
Because at the center (between 2 and 3) the curve is increasing