All categories

3 years ago

If a number is divided in half and the answer is multiplied by 6, how does the final answer compare to the original number?

Mathematics

1 answer:

andrew11 [14]3 years ago

4 0

Answer:

the answer would be 0.

Step-by-step explanation:

this is because if you start with 0 multiply in half you get 0 then times it by 6 you still get 0. so the number sould stay the same. nothing would changed because you cant divide 0 by half. and anything multipled by 0 is still 0.

You might be interested in

If a car moves at a speed of 80 km/h for 5 hours, what distance will it travel?

jarptica [38.1K]

S = D/t

D = S×t

D = 80km/h×5h = 400 km

8 0

3 years ago

Read 2 more answers

Breaks down the problem and give the answer

Natalka [10]

13s=26
s=2
I think those are variables so that would be it.

5 0

4 years ago

Read 2 more answers

What is 4 3/8 - 2 7/8

Artyom0805 [142]

The answer to <span>4 3/8 - 2 7/8 is 1 1/2.</span>

7 0

4 years ago

Read 2 more answers

When a cold drink is taken from a refrigerator, its temperature is 5 degrees C. After 25 minutes in a 20 degrees C room its temp

Leto [7]

Using Newton's Law of Cooling, $\dfrac{dT}{dt} = k(T-T_s)$ , we have $\dfrac{dT}{dt} = k(T - 20)$ ( $T_s$ is 20 degrees). Letting $y = T - 20$ , we get $\dfrac{dy}{dt} = ky$ , so $y(t) = y(0)e^{kt}$ . $y(0) = T(0) - 20 = 5-20 = -15$ , so $y(25) = y(0) e^{25k} = -15e^{25k}$ , and $y(25) = T(25) - 20 = 10 - 20 = -10$ so $-15e^{25k} = -10 \ \ \Rightarrow \ \ e^{25k} = \frac{2}{3}$ . Thus, $25k = \ln\left(\frac{2}{3}\right)$ and $k = \frac{1}{25} \ln\left(\frac{2}{3}\right)$ , so $y(t) = y(0)e^{kt} = -15e^{(1/25)\ln(2/3)t}$ . More simply,
$e^{25k} = \frac{2}{3} \ \ \Rightarrow \ \ e^k = \left( \frac{2}{3} \right)^{1/25}\\ \Rightarrow \ \ e^{kt} = \left( \frac{2}{3} \right)^{t/25}\\
\Rightarrow y(t) = -15 \cdot \left( \frac{2}{3}\right)^{t/25}$

(a) $T(50) = 20 + y(50) = 20-15 \cdot \left( \frac{2}{3}\right)^{50/25}$ =
$20 - 15 \cdot\left(\frac{2}{3}\right)^2 = 20 - \frac{20}{3} = 13.\overline{3}{}^{\circ}C$

13.33333 °C

(b) $15 = T(t) = 20 + y(t) = 20 - 15\cdot\left( \frac{2}{3} \right)^{t/15}$
$\Rightarrow 15 \cdot \left(\frac{2}{3}\right)^{t/25} = 5 \Rightarrow \left( \frac{2}{3} \right)^{t/25} = \frac{1}{3} \Rightarrow$
$(t/25) \ln\left( \frac{2}{3}\right) = \ln\left( \frac{1}{3}\right) \rightarrow t = 25 \ln\left( \frac{1}{3}\right) / \ln\left( \frac{2}{3}\right) \approx 67.74\text{ min}$

67.74 min

4 0

3 years ago

Pls, help :c I don't understand this

lora16 [44]

Answer:

quadratic i think

Step-by-step explanation:

3 0

3 years ago