Question

Janae drew point A located at (-2,5), and point located at (6, -1). What is the x-coordinate of point B that bisects AC? ​

Answer 1

Answer:

The x coordinate is 2

Step-by-step explanation:

Given

$A = (-2,5)$

$C = (6,-1)$

Required

Determine the x coordinate of B

Since B is the bisector of AC, then B is the midpoint and will be calculated using;

$B(x,y) = (\frac{x_1 + x_2}{2},\frac{y_1 + y_2}{2})$

Considering the x coordinates alone;

$x = \frac{x_1 + x_2}{2}$

Where

$(x_1,y_1) = (-2,5)$    and     $(x_2,y_2) = (6,-1)$

Substitute values for x1 and x2

$x = \frac{-2 + 6}{2}$

$x = \frac{4}{2}$

$x = 2$

Hence;

The x coordinate is 2