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pickupchik [31]
3 years ago
5

Help me please and thnk you

Mathematics
1 answer:
madreJ [45]3 years ago
3 0
C is the answer I took a similar test
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AS one of her chores Staci must vacum 1/2 of the house. If she has already vacumed 1/3 of her share tonight whatp part of the li
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Find the area of a parallelogram with the given vertices. P(-2, -5), Q(9, -5), R(1, 5), S(12, 5)
valentina_108 [34]

Answer:

The area of the parallelogram is 55 square unit.

Step-by-step explanation:

The area of a parallelogram is

A=\frac{1}{2}\times base\times height

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Plot these points on a coordinate plane, and draw a perpendicular on PQ from the point R.

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A=\frac{1}{2}\times 11\times 10

A=55

Therefore the area of the parallelogram is 55 square unit.

4 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B%20%5Csec%281%20-%20%20%5Csin%28x%29%20%29%20%7D%20dx" id="TexFormula1" ti
Gnoma [55]

\displaystyle\dfrac{1}{\sec x(1-\sin x)}=\dfrac{\cos x}{1-\sin x}\\\\\\\int \dfrac{dx}{\sec x(1-\sin x)}=\int\dfrac{\cos x\, dx}{1-\sin x}\\\\\\u=1-\sin x\\du=-\cos x\, dx\\\\\int \dfrac{\cos x\, dx}{1-\sin x}=\int \dfrac{-du }{u}=-\int \dfrac{du}{u}=-\ln |u|+C=-\ln|1-\sin x|+C

4 0
2 years ago
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3 years ago
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