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Illusion [34]
4 years ago
14

Using the periodic table of the elements, how many valence electrons would helium have?

Physics
1 answer:
Natali5045456 [20]4 years ago
6 0

Helium only has 2 electrons. So the answer is C. 2

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An 89 kg person climbs up a uniform 13 kg ladder. The ladder is 5.9 m long; its lower end rests on a rough horizontal floor (sta
lapo4ka [179]

Answer:

The maximum distance the person will reach before he slip is 1.82m.

Not even close to the middle of the ladder.

Explanation:

Check attachment for solution

8 0
3 years ago
What is magnetic shielding?<br>​
AysviL [449]
It is basically shielding a magnetic field. This can be done with rubber or any other material that is thick. Normally small magnets already block the shield.
5 0
2 years ago
A mass of 5kg starts from rest and pulls down vertically on a string wound around a disk-shaped, massive pulley. The mass of the
bekas [8.4K]

Answer:

1.98 m/s

Explanation:

To solve this, we would be using the law of conservation of energy, i.e total initial energy is equal to total final energy.

E(i) = E(f)

mgh = ½Iw² + ½mv²

Recall, v = wr, thus, w = v/r

Also, I = ½mr²

I = 0.5 * 5 * 2²

I = 10 kgm²

Remember,

mgh = ½Iw² + ½mv²

Substituting w for v/r, we have

mgh = ½I(v/r)² + ½mv²

Now, putting the values in the equation, we have

5 * 9.8 * 0.3 = ½ * 10 * (v/2)² + ½ * 5 * v²

14.7 = 1.25 v² + 2.5 v²

14.7 = 3.75 v²

v² = 14.7/3.75

v² = 3.92

v = √3.92

v = 1.98 m/s

Thus, the speed is 1.98 m/s

5 0
3 years ago
What is located in the exosphere?
Paha777 [63]
In the exosphere, there is thin air, since it is the uppermost level in the atmosphere. It is made mostly of helium and hydrogen. But, traces of other gases such as atomic oxygen and carbon dioxide can also be found in the exosphere.
7 0
4 years ago
In this video, the linear motion of the descending sphere is directly related to the rotational motion of the wheel, and in orde
matrenka [14]

Explanation:

Let a is the linear acceleration of the descending sphere. It is given by,

a=\dfrac{dv}{dt}.......(1) (change in velocity)

Let \alpha is the  angular acceleration α of the rotating wheel. It is given by :

\alpha =\dfrac{d\omega}{dt}............(2) (change in angular velocity)

Dividing equation (1) and (2) we get :

\dfrac{a}{\alpha }=\dfrac{dv}{d\omega}

Since, v=r\omega

\dfrac{a}{\alpha }=\dfrac{d(r\omega)}{d\omega}

\dfrac{a}{\alpha }=r

a=\alpha r

a=\alpha \times r

Hence, this is the required solution.

8 0
3 years ago
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