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3 years ago

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What is Introducing to Momentum

1 answer:

Diano4ka-milaya [45]3 years ago

5 0

Answer:

Momentum can be defined as "mass in motion." All objects have mass; so if an object is moving, then it has momentum - it has its mass in motion. The amount of momentum that an object has is dependent upon two variables: how much stuff is moving and how fast the stuff is moving.

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A single beam of light is shone into a glass containing milky water.

Bumek [7]

Answer:

the first one

Explanation:

3 0

3 years ago

The take-up reel of a cassette tape has a radius of 2.5 cm. Find the length of the tape that passes around the reel in 7.1 s whe

Jet001 [13]

Answer:

s = 0.337 m

Explanation:

First, we will find the angular displacement of the reel:

$\theta = \omega t$

where,

θ = angular displacement = ?

ω = angular speed = 1.9 rad/s

t = time taken = 7.1 s

Therefore,

θ = (1.9\ rad/s)(7.1 s)

θ = 13.5 rad

Now, we will find out the length of tape:

s = rθ

where,

s = length of tape = ?

r = radius of reel = 2.5 cm = 0.025 m

Therefore,

s = (0.025 m)(13.5 rad)

<u>s = 0.337 m</u>

6 0

3 years ago

a truck is moving around a circular curve @ a uniform velocity of 13m/s. if the centifrical force on truck is 3,300N with truck

VMariaS [17]

<u>Answer</u>

81.94 m

<u>Explanation</u>

The centripetal force of an object moving in a circular path is given by:

F = mv²/r Where m is the mass of the object, v is the constant velocity and r is the radius of the curve.

F = mv²/r

3,300 = (1600×13²)/r

3,300 = 270,400/r

r = 270,400/3,300

= 81.94 m

8 0

3 years ago

Calculate the mass of air of density 1.2kgm-3 in a room of dimensions 8m by 6m by 4m.

77julia77 [94]

Answer:

230.4kg

Explanation:

volume of the room = l× b×h

volume= 8×6×4

volume=192m3

density= mass/volume

hence mass= density × volume

mass= 1.2kgm-3 × 192m3

mass= 230.4kg

5 0

2 years ago

Estimate the number of Ping-Pong balls that can be packed into an average size room (without crushing them). Given that Ping-Pon

scoray [572]

Answer: 3,893,845.918 Ping-Pong balls

Explanation:

The volume of an average room is:

$V_{room}=(length)(width)(height)$ (1)

$V_{room}=(12 ft)(18 ft)(9 ft)=1944 ft^{3}$ (2)

Now let’s transform this $V_{room}$ to units of $cm^{3}$ , knowing $1 ft=30.48 cm$ :

$V_{room}=1944 ft^{3}\frac{{(30.48 cm)}^{3}}{1ft^{3}}=55,047,949.78 cm^{3}$ (3)

On the other hand, we have Ping-Pong balls with a radius $r=1.5 cm$ , and their volume is given by:

$V_{balls}=\frac{4}{3} \pi r^{3}$ (4)

$V_{balls}=\frac{4}{3} \pi (1.5 cm)^{3}$ (5)

$V_{balls}=14.137 cm^{3}$ (6)

Now, the number $n$ of Ping-Pong balls that can be packed into the room is:

$n=\frac{V_{room}}{V_{balls}}$ (7)

$n=\frac{55,047,949.78 cm^{3}}{14.137 cm^{3}}$ (8)

$n=3,893,845.918$ This is the number of Ping-Pong balls that can be packed into an average size room

7 0

3 years ago