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irga5000 [103]
3 years ago
8

297.3 = 2hundred, 9tens, 7 ones, and 3 tenths. Regroup 297.3 using 2 hundred, 9 tens, 5 ones, and ? tenths

Mathematics
1 answer:
Mashcka [7]3 years ago
5 0
23 would be the answer hope it helps
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<img src="https://tex.z-dn.net/?f=5x%5E%7B2%7D%20%2B11x%2B2%3D0" id="TexFormula1" title="5x^{2} +11x+2=0" alt="5x^{2} +11x+2=0"
eimsori [14]

The solutions to the quadratic equation in the exact form are x = -1/2 or x = -5

<h3>What are quadratic equations?</h3>

Quadratic equations are second-order polynomial equations and they have the form y = ax^2 + bx + c or y = a(x - h)^2 + k

<h3>How to determine the solution to the quadratic equation?</h3>

A quadratic equations can be split to several equations and it can be solved as a whole

In this case, the quadratic equation is given as

5x^2 + 11x + 2 = 0

Using the form of the quadratic equation y = ax^2 + bx + c, we have

a = 5, b = 11 and c = 2

The quadratic equation can be solved using the following formula

x = (-b ± √(b^2 - 4ac))/2a

Substitute the known values of a, b and c in the above equation

x = (-11 ± √(11^2 - 4 * 5 * 2))/2*2

Evaluate the exponent

x = (-11 ± √(121 - 4 * 5 * 2))/2*2

Evaluate the products

x = (-11 ± √(121 - 40))/4

Evaluate the sum

x = (-11 ± √(81))/4

Take the square root of 81

x = (-11 ± 9)/4

Expand

x = 1/4 * (-11 + 9) or x = 1/4 * (-11 - 9)

Evaluate the difference

x = 1/4 * -2 or x = 1/4 * -20

Evaluate the product

x = -1/2 or x = -5

Hence, the solutions to the quadratic equation in the exact form are x = -1/2 or x = -5

Read more about quadratic equations at

brainly.com/question/1214333

#SPJ1

4 0
2 years ago
If 8km= 5 miles convert 160km into miles
d1i1m1o1n [39]

Answer:

99.4194

Step-by-step explanation:

8 0
2 years ago
What is the value of m? 12+(7+m)=30<br><br> 11<br> 19<br> 25<br> 35<br> 49
Marat540 [252]
The answer is 11
hope that helps
4 0
3 years ago
Read 2 more answers
What happens to the mode of the data set shown below if
nlexa [21]

Answer:

OB) The mode does not change

8 0
3 years ago
The magnitude and direction of two vectors are shown in the diagram. What is the magnitude of their sum? ​
VLD [36.1K]

Separate the vectors into their <em>x</em>- and <em>y</em>-components. Let <em>u</em> be the vector on the right and <em>v</em> the vector on the left, so that

<em>u</em> = 4 cos(45°) <em>x</em> + 4 sin(45°) <em>y</em>

<em>v</em> = 2 cos(135°) <em>x</em> + 2 sin(135°) <em>y</em>

where <em>x</em> and <em>y</em> denote the unit vectors in the <em>x</em> and <em>y</em> directions.

Then the sum is

<em>u</em> + <em>v</em> = (4 cos(45°) + 2 cos(135°)) <em>x</em> + (4 sin(45°) + 2 sin(135°)) <em>y</em>

and its magnitude is

||<em>u</em> + <em>v</em>|| = √((4 cos(45°) + 2 cos(135°))² + (4 sin(45°) + 2 sin(135°))²)

… = √(16 cos²(45°) + 16 cos(45°) cos(135°) + 4 cos²(135°) + 16 sin²(45°) + 16 sin(45°) sin(135°) + 4 sin²(135°))

… = √(16 (cos²(45°) + sin²(45°)) + 16 (cos(45°) cos(135°) + sin(45°) sin(135°)) + 4 (cos²(135°) + sin²(135°)))

… = √(16 + 16 cos(135° - 45°) + 4)

… = √(20 + 16 cos(90°))

… = √20 = 2√5

5 0
3 years ago
Read 2 more answers
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