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3 years ago

(5a^3-2a^2)+(6a^3+9a^2+8a)

Mathematics

1 answer:

Gnom [1K]3 years ago

8 0

Answer:

11a^3 + 7a^2 + 8a

Step-by-step explanation:

( 5a^3 - 2a^2 ) + ( 6a^3 + 9a^2 + 8a )

= 5a^3 + 6a^3 + -2a^2 + 9a^2 + 8a

= 11a^3 + 7a^2 + 8a

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RSB [31]

Answer:

Identity is true

Step-by-step explanation:

$\frac{cos\theta+1}{tan^2\theta}=\frac{cos\theta}{sec\theta-1}$

$(cos\theta+1)(sec\theta-1)=(tan^2\theta)(cos\theta)$

$(cos\theta)(sec\theta)+(cos\theta)(-1)+(1)(sec\theta)+(1)(-1)=(\frac{sin^2\theta}{cos^2\theta})(cos\theta)$

$(cos\theta)(\frac{1}{cos\theta})-cos\theta+sec\theta-1=\frac{sin^2\theta}{cos\theta}$

$1-cos\theta+sec\theta-1=\frac{sin^2\theta}{cos\theta}$

$-cos\theta+sec\theta=\frac{sin^2\theta}{cos\theta}$

$sec\theta-cos\theta=\frac{sin^2\theta}{cos\theta}$

$\frac{1}{cos\theta}-cos\theta=\frac{sin^2\theta}{cos\theta}$

$\frac{1}{cos\theta}-\frac{cos^2\theta}{cos\theta}=\frac{sin^2\theta}{cos\theta}$

$\frac{1-cos^2\theta}{cos\theta}=\frac{sin^2\theta}{cos\theta}$

$\frac{sin^2\theta}{cos\theta}=\frac{sin^2\theta}{cos\theta}$

Therefore, the identity is true.

<u>Helpful tips:</u>

Pythagorean Identity: $sin^2\theta+cos^2\theta=1\\cos^2\theta=1-sin^2\theta\\sin^2\theta=1-cos^2\theta$

Quotient Identities: $tan\theta=\frac{sin\theta}{cos\theta},sec\theta=\frac{1}{cos\theta}$

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3 years ago

The opposite of -a is always positive. True or false?<br> Answer it FAST please!!

musickatia [10]

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Step-by-step explanation:

The opposite of any negative number (a) will always be positive because -a is the opposite of +a

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defon

Answer:

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Step-by-step explanation:

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Natali5045456 [20]

Answer:

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3 years ago

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√324 * √75 = √24300 = 90√3
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