Answer:
The time taken for the projectile to reach the given height is 1.2 s.
Step-by-step explanation:
Given;
height of travel, h = 25 ft
initial velocity of the projectile, u = 15 ft/s
The time taken for the projectile to travel a height of 25 ft is given by the following kinematic equation;
h = ut + ¹/₂gt²
25 = 15t + ¹/₂(9.8)t²
25 = 15t + 4.9t²
4.9t² + 15t - 25 = 0
solving the quadratic equation, we will have the following solution of t;
t = 1.2 s
Therefore, the time taken for the projectile to reach the given height is 1.2 s.
I hope this helps you
10^2=|aq|^2+5^2
100-25= |aq|^2
75= |aq|^2
aq= 5 square root of 3
this triangle 30-60-90
Answer:
0.4
Step-by-step explanation:
Vicki has a computer randomly select 0 or 1 three times, with 0 representing <u>heads</u> and 1 representing <u>tails</u>. The results of 15 trials are shown in the table.
110 111 000 011 000
010 101 100 000 000
111 101 110 101 111
Vicki would like to estimate the probability of tails (1) coming up fewer than 2 times (must be 0 or 1 digit 1 in record). All such seuences are marked in bold int the above table. There are 6 such trails. Hence, Vicki's estimated probability, based on this simulation is
