Answer:
not arithmetic
Step-by-step explanation:
An arithmetic sequence has a common difference d between consecutive terms.
Given
= 2n² - 1
Substitute in n = 1, 2, 3, 4 to generate the first 4 terms of the sequence
= 2(1)² - 1 = 2 - 1 = 1
= 2(2)² - 1 = 8 - 1 = 7
= 2(3)² - 1 = 18 - 1 = 17
= 2(4)² - 1 = 32 - 1 = 31
check the difference between consecutive terms
7 - 1 = 6
17 - 7 = 10
31 - 17 = 14
The differences are not common hence not an arithmetic sequence
90kg of sand had been puted in 3 bags but in 2+3+7=12 parts.
90kg/12=7.5kg
Small bag has 2 parts which is 7.5kg*2=15kg
Medium bag has 3 parts which is 7.5kg*3=22.5kg
Large bag has 7 parts which is 7.5kg*7=52.5kg
2:3:7=15kg:22.5kg:52.5kg
15kg+22.5kg+52.5kg=90kg
Answer:
The third score must be larger than or equal to 72, and smaller than or equal 87
Step-by-step explanation:
Let's name "x" the third quiz score for which we need to find the values to get the desired average.
Recalling that average grade for three quizzes is the addition of the values on each, divided by the number of quizzes (3), we have the following expression for the average:

SInce we want this average to be in between 80 and 85, we write the following double inequality using the symbols that include equal sign since we are requested the average to be between 80 and 85 inclusive:

Now we can proceed to solve for the unknown "x" treating each inaquality at a time:

This inequality tells us that the score in the third quiz must be larger than or equal to 72.
Now we study the second inequality to find the other restriction on "x":

This ine
quality tells us that the score in the third test must be smaller than or equal to 87 to reach the goal.
Therefore to obtained the requested condition for the average, the third score must be larger than or equal to 72, and smaller than or equal 87:
Answer:
Solution given:
Volume of cone=⅓πr²h
Volume of cylinder=πr²h
1.
volume =πr²h=π*(10/2)²*6=<u>471.23mm³</u>
2.
Volume =πr²h=π*8*12.5=<u>314.16in³</u>
3.
volume =⅓πr²h=⅓*π*4²*3=<u>5</u><u>0</u><u>.</u><u>2</u><u>6</u><u>c</u><u>m</u><u>³</u>
4.
Volume =⅓πr²h=⅓*π*(8/2)²*12=<u>2</u><u>0</u><u>1</u><u>.</u><u>0</u><u>6</u><u>i</u><u>n</u><u>³</u>
Answer:
It’s prime
Step-by-step explanation:
Numbers between 2 and 31 are since these only have 1 and itself.