Ask question

Ask question

All categories

3 years ago

9

What is the converse of the statement? If a point lies in Quadrant III, then its coordinates are both negative. If the coordinat

es of a point are both negative, then the point is in Quadrant III. If the coordinates of a point are both negative, then the point is not in Quadrant I. If a point is in Quadrant I, then its coordinates are both positive. If the coordinates of a point are both negative positive, then the point is not in Quadrant II.

2 answers:

Vladimir [108]3 years ago

6 0

<h2>Answer:</h2>

The converse statement is:

If the coordinates of a point are both negative, then the point is in Quadrant III.

<h2>Step-by-step explanation:</h2>

We know that for any conditional statement of the type:

If p then q i.e. p → q

where p is the hypothesis and q is the conclusion.

The converse of the statement is given by:

If q then p i.e. q → p.

We are given a statement as:

If a point lies in Quadrant III, then its coordinates are both negative.

i.e. Here p=Point lie in Quadrant III

and q= Coordinates are both negative.

Hence, the converse statement will be:

If the coordinates of a point are both negative, then the point is in Quadrant III.

Dovator [93]3 years ago

5 0

<span>If the coordinates of a point are both negative, then the point is in Quadrant III.

</span>

You might be interested in

What is the slope of the line that passes through the points(-5,-9) and (-5,-13)? Write your answer in simplest form.

Valentin [98]

Answer:

slope is undefined

ex. a straight vertical line like x = 2 would have an undefined slope

Step-by-step explanation:

formula is

y2-y1 / x2-x1

-13 + 9 / -5 + 5

-4 / 0

slope is undefined

straight vertical line like x = 2 would have an undefined slope

undefined slope is the slope of any vertical line that goes up or down. There is no horizontal movement and hence the denominator is zero while calculating the slope. Thus the slope of the line is undefined.

cuemathcomgeometryundefinedslope

mathbootcampscom

7 0

2 years ago

What property is -3(m+8)=-3m-24

Damm [24]

Answer:

All real numbers are solutions.

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

−3(m+8)=−3m−24

(−3)(m)+(−3)(8)=−3m+−24(Distribute)

−3m+−24=−3m+−24

−3m−24=−3m−24

Step 2: Add 3m to both sides.

−3m−24+3m=−3m−24+3m

−24=−24

Step 3: Add 24 to both sides.

−24+24=−24+24

0=0

Answer:

All real numbers are solutions.

8 0

3 years ago

2. Consider the circle x^2−4x+y^2+10y+13=0. There are two lines tangent to this circle having a slope of 2/3.

likoan [24]

Answer:

a) The coordinates are (0.431, -2.646) and (3.568,-7.354)

b) The tangent lines are

l₁ = (x-0.431)*2/3 - 2.646

l₂ = (x-3.568)2/3 - 7.354

Step-by-step explanation:

First, lets complete squares, by taking for each cordinate the square of a linear expression

0= x²−4x+y²+10y+13 = (x-2)²+ 4 + (y+5)²-25+13 = (x-2)²+(y+5)² - 8

Hence (x-2)² + (y+5)² = 8

Lets put y in function of x. We should obtain 2 functions f and g that represent the circle.

(y+5)² = 8 - (x-2)² = -x² + 4x + 4

$y = ^+_- \sqrt{-x^2+4x+4} -5$

Thus

$f(x) = \sqrt{-x^2+4x+4} - 5$

$g(x) = -\sqrt{-x^2+4x+4} - 5$

Lets find the derivate of each function and the points in which they reach the value 2/3. In those points the tangent line will have a slope of 2/3.

We may just find the values of x which the derivate of f is either 2/3 or -2/3.

$\frac{-x+2}{\sqrt{-x^2+4x+4}} = ^+_-\frac{2}{3} \Leftrightarrow \frac{x^2-4x+4}{-x^2+4x+4} = \frac{4}{9} \Leftrightarrow 9(x^2-4x+4) = 4(-x^2+4x+4) \\\Leftrightarrow 13x^2-52x+20 = 0$

The quadratic has roots

$\frac{52 ^+_-\sqrt{1664}}{26}$

one root is 3.568, which corresponds with g, and the other root is 0.431, corresponding to f.

Also g(3.568) = - 7.354 and f(0.431) = -2.646

This means that the coordinates are (0.431 , -2.646), (3.568 , -7.354) and the tangent lines are

l₁ = (x-0.431)*2/3 - 2.646

l₂ = (x-3.568)2/3 - 7.354

5 0

2 years ago

Someone please help me ??

KATRIN_1 [288]

Answer:

A filled in circle indicates "or equal to" in a graphing situation. If it's open it means anything less than or greater then that number depending on whatever your graph looks like.

Hopefully this helped!

5 0

3 years ago

Read 2 more answers

Assume the acceleration of the object is a(t) = −32 feet per second per second. (Neglect air resistance.) A balloon, rising vert

Liula [17]

Answer:

(a) 2.79 seconds after its release the bag will strike the ground.

(b) At a velocity of 73.28 ft/second it will hit the ground.

Step-by-step explanation:

We are given that a balloon, rising vertically with a velocity of 16 feet per second, releases a sandbag at the instant when the balloon is 80 feet above the ground.

Assume the acceleration of the object is a(t) = −32 feet per second.

(a) For finding the time it will take the bag to strike the ground after its release, we will use the following formula;

$s=ut+\frac{1}{2} at^{2}$

Here, s = distance of the balloon above the ground = - 80 feet

u = intital velocity = 16 feet per second

a = acceleration of the object = -32 feet per second

t = required time

So, $s=ut+\frac{1}{2} at^{2}$

$-80=(16\times t)+(\frac{1}{2} \times -32 \times t^{2})$

$-80=16t-16 t^{2}$

$16 t^{2} -16t -80 =0$

$t^{2} -t -5 =0$

Now, we will use the quadratic D formula for finding the value of t, i.e;

$t = \frac{-b\pm \sqrt{D } }{2a}$

Here, a = 1, b = -1, and c = -5

Also, D = $b^{2} -4ac$ = $(-1)^{2} -(4 \times 1 \times -5)$ = 21

So, $t = \frac{-(-1)\pm \sqrt{21 } }{2(1)}$

$t = \frac{1\pm \sqrt{21 } }{2}$

We will neglect the negative value of t as time can't be negative, so;

$t = \frac{1+ \sqrt{21 } }{2}$ = 2.79 ≈ 3 seconds.

Hence, after 3 seconds of its release, the bag will strike the ground.

(b) For finding the velocity at which it hit the ground, we will use the formula;

$v=u+at$

Here, v = final velocity

So, $v=16+(-32 \times 2.79)$

v = 16 - 89.28 = -73.28 feet per second.

Hence, the bag will hit the ground at a velocity of -73.28 ft/second.

8 0

3 years ago