Answer:
Take the first two expressions (you can actually take any two expressions): $\frac{a+b-c}{c}=\frac{a-b+c}{b}$.
$\frac{a+b}{c}=\frac{a+c}{b}$
$ab+b^2=ac+c^2$
$a(b-c)+b^2-c^2=0$
$(a+b+c)(b-c)=0$
$\Rightarrow a+b+c=0$ OR $b=c$
The first solution gives us $x=\frac{(-c)(-a)(-b)}{abc}=-1$.
The second solution gives us $a=b=c$, and $x=\frac{8a^3}{a^3}=8$, which is not negative, so this solution doesn't work.
Therefore, $x=-1\Rightarrow\boxed{A}$.
Step-by-step explanation:
1 is 4a+15b
2 is 5x-4
3 is 2x-22
4 is 8x-21
5 is 25x + 55
6 is 55x - 17
Step-by-step explanation:
2^3x^5×3y^2×3
8x^15y^6
Answer:
he found 24 coins
Step-by-step explanation:
Answer: try to (x) each one by the answer to -0.0035 +70
Step-by-step explanation:
