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trasher [3.6K]
3 years ago
14

Could someone please help me with this

Mathematics
2 answers:
nevsk [136]3 years ago
8 0
It is 6 5/12 hope this helps!
skelet666 [1.2K]3 years ago
5 0
6 5/12 is the correct answer
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Please help me with this question I’m stuck!
Natasha_Volkova [10]
12 is the answer.

The sequence is 12, 6, 3, 3/2
8 0
4 years ago
A stock has a 25% probability of increasing by $10 and a 75% probability of decreaing by $5. What is the stocks expected increas
statuscvo [17]

Step-by-step explanation:

The expected value is the sum of each probability times the value.

E = 0.25 (10) + 0.75 (-5)

E = -1.25

The stock is expected to decrease by $1.25.

6 0
3 years ago
Estimate the length of one side of a square floor if the area is 320 square feet. Round to the nearest whole number.
igomit [66]
So if the area of a square is 320 square meters, then because all four sides are equal, you would end up with the equation x^{2}=320 which simplifies to 
5 0
3 years ago
Find the measure of an angle whose supplement is 4 times as large as its complement
Nady [450]
Try this less than 90 degrees or abtuse angle
6 0
4 years ago
Read 2 more answers
Jamison graphs the function ƒ(x) = x4 − x3 − 19x2 − x − 20 and sees two zeros: −4 and 5. Since this is a polynomial of degree 4
Art [367]

We are given polynomial function f(x)=x^4-x^3-19x^2-x-20

We are given two zeros -4 and 5.

Therefore, x=-4 and x=5 is given.

So, the two factors of the polynomial will be (x+4)(x-5).

Let us write some steps to factor the given polynomial.

Let us take above factor (x+4) first.

On factoring (x+4) we get factors

x^4-x^3-19x^2-x-20=\left(x+4\right)\left(x^3-5x^2+x-5\right)

\mathrm{:Let \ us \ factor}\:x^3-5x^2+x-5 \ now.

Grouping

=\left(x^3-5x^2\right)+\left(x-5\right)

Factoring out gcf from each group, we get

=x^2\left(x-5\right)+\left(x-5\right)

=\left(x-5\right)\left(x^2+1\right)

So, the final factored form of given polynomial will be

x^4-x^3-19x^2-x-20=\left(x+4\right)\left(x-5\right)\left(x^2+1\right)

For first to factors (x+4) and (x-5) we have given roots: -4 and 5.

Let us find the root of third factor we got.

x^2+1=0

Subtracting both sides by 1.

x^2 = - 1.

On taking square root on both sides, we get a square root(-1)

x=\sqrt{-1}=+ i and -i.

Those are imaginary solutions.

Therefore, correct option is B) No, there are two imaginary solutions.



5 0
4 years ago
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