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3 years ago

What is 639.03 rounded to tenths place ?

Mathematics

1 answer:

butalik [34]3 years ago

4 0

Answer:

639.0

Step-by-step explanation:

639.03

3 is less than 5 so you round down havening 0 stay the same

639.0

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Solve the following...<br>6x - 5 = -9x -9

sergiy2304 [10]

$\quad \huge \quad \quad \boxed{ \tt \:Answer }$

$\qquad \tt \rightarrow \:x = -\cfrac{4}{15}$

____________________________________

$\large \tt Solution \: :$

$\qquad \tt \rightarrow \: 6x - 5 = - 9x - 9$

[ add 9x and 5 on both sides ]

$\qquad \tt \rightarrow \: 6x - 5 + 9x + 5 = - 9x - 9 + 9x + 5$

$\qquad \tt \rightarrow \: 6x + 9x = - 9 + 5$

$\qquad \tt \rightarrow \: 15x = - 4$

$\qquad \tt \rightarrow \: x = - \cfrac{4}{15}$

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

7 0

2 years ago

Read 2 more answers

Ill give brainliest and 5 stars and thanks if answer this what is the result of substituting for y in the bottom equation

GREYUIT [131]

We have two set of solutions , ( $\frac{\sqrt{29} }{2}$ , $\frac{\sqrt{29} }{2}$ + 3 ) , ( - $\frac{\sqrt{29} }{2}$ + 3 , - $\frac{\sqrt{29} }{2}$ + 3).

<u>Step-by-step explanation:</u>

We have , the following equations:

$y = x+3$ and $y = x^{2} +2x -4$ . Let's substitute value of y in bottom equation:

⇒ $y = x^{2} +2x -4$

⇒ $x+3 = x^{2} +2x -4$

⇒ $x^{2} +x -7= 0$

Roots of quadratic equation are given by: a = 1, b= 1 , c = -7

$x = \frac{\sqrt{b^{2}-4ac} }{2a}$

⇒ $x = \frac{\sqrt{b^{2}-4ac} }{2a}$

⇒ $x = \frac{\sqrt{1^{2}-4(1)(-7)} }{2(1)}$

⇒ $x = \frac{\sqrt{29} }{2}$ which is actually x = ± $\frac{\sqrt{29} }{2}$ .

We know that $y = x+3$ ,

⇒ y = ± $\frac{\sqrt{29} }{2}$ + 3.

We have two set of solutions , ( $\frac{\sqrt{29} }{2}$ , $\frac{\sqrt{29} }{2}$ + 3 ) , ( - $\frac{\sqrt{29} }{2}$ + 3 , - $\frac{\sqrt{29} }{2}$ + 3).

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3 years ago

If y = -10 -x, find y when x = -2

arlik [135]

Answer:

y = -8

Step-by-step explanation:

y = -10 - x

y = -10 - (-2)

y = -10 + 2

y = -8

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3 years ago

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Yoko's call lasted for 47 minutes.

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fenix001 [56]

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