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maw [93]
2 years ago
5

What is the ratio of inches to feet on measuring tape?

Mathematics
1 answer:
Zigmanuir [339]2 years ago
3 0
12 inches in 1 foot so 12:1
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I don't know if this is right... please someone help mee
worty [1.4K]
For the first circle, let's use the pythagorean theorem

\bf \textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
c=\sqrt{8^2+15^2}\implies c=\sqrt{289}\implies c=17

now, it just so happen that the hypotenuse on that triangle, is actually 17, but we used the pythagorean theorem to find it, and the pythagorean theorem only works for right-triangles.

 so if the hypotenuse is actually 17, that means that triangle there is actually a right-triangle, meaning that the radius there, and the outside line there, are both meeting at a right-angle.

when an outside line touches the radius line, and they form a right-angle, the outside line is indeed a tangent line, since the point of tangency is always a right-angle with the radius.



now, let's check for second circle

\bf \textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
c=\sqrt{11^2+14^2}\implies c=\sqrt{317}\implies c\approx 17.8044938

well, low and behold, we didn't get our hypotenuse as 16 after all, meaning, that triangle is NOT a right-triangle, and that outside line is not touching the radius at a right-angle, therefore is NOT a tangent line.



let's check the third circle

\bf \textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
c=\sqrt{33^2+56^2}\implies c=\sqrt{4225}\implies c=\stackrel{33+32}{65}

this time, we did get our hypotenuse to 65, the triangle is a right-triangle, so the outside line is indeed a tangent line.
6 0
2 years ago
HELP WILL MARK BRAINLIEST!
denpristay [2]

Answer:

All the exponents in the algebraic expression must be non-negative integers in order for the algebraic expression to be a polynomial. As a general rule of thumb if an algebraic expression has a radical in it then it isn't a polynomial

so no its not.

3 0
2 years ago
Read 2 more answers
3. Find the circumcenter of triangle ABC with A(1,6), B(1,4), C(5,4). (1point). a)(5,3). b)(3,5). c)(7.3). d)(1,7). 5.What is th
Harrizon [31]

For problem number 3, the answer is (3, 5). The correct answer between all the choices given is the second choice or letter B.

For problem number 5, the answer is median. The correct answer between all the choices given is the third choice or letter C.

I am hoping that these answers have satisfied your queries and it will be able to help you, and if you’d like, feel free to ask another question.

6 0
3 years ago
Read 2 more answers
Thx for ur helpness click the picture
Mnenie [13.5K]

Answer:

Commission = $52.20

Step-by-step explanation:

The commission is the cost of the item multiplied by the commission rate

Commission = 348 * .15

Commission = 52.20

3 0
3 years ago
A polygon with 3 sides is stacked to form a prism. Which is the base shape of this prism? 1. square 2. trapezoid 3. triangle 4.
PilotLPTM [1.2K]
Triangular prism. It has three sides so a triangle
7 0
3 years ago
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