Answer:
20 grams of an alloy containing 25% silver has to be melted with 50 grams of an alloy containing 60% silver to obtain a final alloy containing 50% silver
Step-by-step explanation:
Hi
We define
, wich means alloy a has 50 grams containing 60% silver.
, wich means alloy b has x grams containing 25% silver.
So we can build an equiation
, as half of the final alloy has to be silver. Then solving for x

Wich means 20 grams of an alloy containing 25% silver (
) has to be melted with 50 grams of an alloy containing 60% silver (
) to obtain a final alloy containing 50% silver.
The volume:
Pi x r^2 x h
V = pi x 12^2 x 7
V = 1008pi units^3
The answer would be a
hope it helps.
If the recipe needs 200g of chocolate bars, and that recipe feeds 8 people, you need to figure out how many times you'd have to make a recipe to feed 50 people.
50 is not a factor of 8, so we have to break the recipe down. if 200g of chocolate feeds 8 people, then it's safe to assume that 100g feeds 4 people, and 50g feeds 2 people.
The closest you get to 50 without exceeding it by a factor of 8 is 6 x 8= 48. You'd be missing the chocolate for two people, all you have to do is add 50 grams of a chocolate bar.
You have to multiply each ingredient by 6 therefore everything is exactly the same, just amplified. 200 x 6 =1200, which means you'd need 1200g of chocolate bars + 50g to make a mousse for 50 people.
Each chocolate bar has 150g, so now what you do is you get the 1250g and divide it by 150g. This will tell you the amount of chocolate bars you need to complete the recipe for 50 people. The answer is 8.33333, which means Tim will have to buy 9 chocolate bars.
Answer:
16
Step-by-step explanation:
10 · 4 = 40
640/40= 16
Division yields

Now for partial fractions: you're looking for constants <em>a</em>, <em>b</em>, and <em>c</em> such that


which gives <em>a</em> + <em>b</em> = 2, <em>c</em> = 0, and 2<em>a</em> = -7, so that <em>a</em> = -7/2 and <em>b</em> = 11/2. Then

Now, in the integral we get

The first two terms are trivial to integrate. For the third, substitute <em>y</em> = <em>x</em> ² + 2 and d<em>y</em> = 2<em>x</em> d<em>x</em> to get
