Answer:
Step-by-step explanation:
Left Hand Side
Change to sin(theta) and cos(theta)
csc(theta) = 1/sin(theta)
cot(theta) = cos(theta)/sin(theta)
1/sin(theta) - cos(theta)/sin(theta) Put over Sin(theta) Common denominator
[1 - cos(theta)] / sin(theta) Multiply numerator and denominator by 1 + cos(theta)
(1 - cos(theta)(1 + cos(theta) ) / sin(thata)*(1 + cos(theta))
(1 + cos(theta)(1 - cos(theta)) = 1 - cos^2(theta)
sin^2(theta) / (sin(theta)* ( 1 + cos(theta)
sin(theta) / (1 + cos(theta) )
Right hand Side.
See Above.
Answer:
2565
Step-by-step explanation:
:)
Answer:
Alyssa's team won 20 games.
Step-by-step explanation:
We can introduce a variable that represents how many games Alyssa's team won.
Let x<em> </em>represent how many games Alyssa's team won.
We can now create a expression, we know that her team won 5 out of 7 games which would be equivalent to the fraction 5/7. We also know her team has played 28 games and five sevenths (5/7) of those they won.
This would give us the expression 5/7 = x/28.
We need to do this because 5/7 is equivalent to x the numbers of games they won over 28 the number of games they played.
Solving for 5/7 = x/28 we have:
5/7 = x/28
We need to isolate x on the right side to do so we can multiply both sides by 28.
5/7 * 28 = x/28*28 simplifying
20 = x.
Therefore the number of games Alyssa's team won is 20 games.
Answer: The correct option is (B) 1625.2 miles.
Step-by-step explanation: Given that at a given speed a car can travel 95.6 miles on 4 gallons of gasoline.
We are to find the distance that the car can travel on 68 gallons at the same speed.
We will be using the UNITARY method to solve the given problem.
Distance traveled by the car on 4 gallons of gasoline = 95.6 miles.
So, the distance traveled by the car on 1 gallon of gasoline will be
Therefore, the distance traveled by the car in 68 gallons of gasoline is given by
Thus, the required distance traveled by the car on 68 gallons of gasoline is 1625.2 miles.
Option (B) is CORRECT.
