Answer:
a. 47
b. 87
c. 127
Step-by-step explanation:
Assume a total of 4 exams ( first 3 plus a final)
Let final score be X,
Hence, average score = (85 + 71 + 77 + x) / 4 = (233 + x) / 4
a) to get a C, the average score must be 70
70 = (233 + x) / 4
(233 + x) = 70 (4) = 280
x = 280 - 233 = 47 (Ans)
b) to get a B, the average score must be 80
80 = (233 + x) / 4
(233 + x) = 80 (4) = 320
x = 320 - 233 = 87 (Ans)
c) to get a A, the average score must be 90
90 = (233 + x) / 4
(233 + x) = 90 (4) = 360
x = 360 - 233 = 127 (Ans)
Answer:
f(2)= 11
Step-by-step explanation:
you have to substitute 2 for every x you see:
f(x) = 3x² + 2x - 5
f(2)= 3(2)^2+2(2)-5
f(2)= 11
Answer:
10.3727253..., irrational
Step-by-step explanation:
(a) P( fifth one is bad) = P( first 4 are OK) * P(5th is bad)
= (0.98)^4 * 0.02 = 0.0184 or 1.84%
(b) this will be (0.98)^10 = 81.70%
Answer:
31
Step-by-step explanation:
time is tricky due to the 60 minute interface. In those questions add to the lower number until you hit a rounded number.
Fortunately you don't need to use this in this problem, and can just subtract 58-27 to get 31