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TEA [102]
3 years ago
6

You have 2 types of bread, 3 types of meat, and 2 types of cheese. How many different sandwiches can you make if each sandwich h

as 1 type of bread, 1 type of meat, and 1 type of cheese?
Mathematics
1 answer:
Tamiku [17]3 years ago
6 0
You would obviously only be able to create two sandwiches with the given information.
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The equation of a line given two points needs to be found. Samuel claims that slope-intercept form will generate the equation an
Zigmanuir [339]

The answer is:put the equation xa+yb=1 to the slope intercept form and find its slope and y-intercept.

3 0
3 years ago
What is the simplified form of the following expression? 7(3sqrt2x)-3(3sqrt16x)-3(3sqrt8x)
coldgirl [10]

Assignment: \bold{Simplify \ Equation: \ 7\left(3\sqrt{2}x\right)-3\left(3\sqrt{16}x\right)-3\left(3\sqrt{8}x\right)}

<><><><><><><>

Answer: \boxed{\bold{3\sqrt{2}x-36x}}

<><><><><><><>

Explanation: \downarrow\downarrow\downarrow

<><><><><><><>

[ Step One ] Remove Parenthesis (a) = a

\bold{7\cdot \:3\sqrt{2}x-3\cdot \:3\sqrt{16}x-3\cdot \:3\sqrt{8}x}

[ Step Two ] Simplify Equations

\bold{7\cdot \:3\sqrt{2}x: \ 21\sqrt{2}x}

\bold{3\cdot \:3\sqrt{16}x: \ 36x}

\bold{3\cdot \:3\sqrt{8}x: \ 18\sqrt{2}x}

[ Step Three ] Rewrite Equation

\bold{21\sqrt{2}x-36x-18\sqrt{2}x}

[ Step Four ] Add Similar Elements

\bold{21\sqrt{2}x-18\sqrt{2}x=3\sqrt{2}x}

[ Step Five ] Rewrite Equation

\bold{3\sqrt{2}x-36x}

<><><><><><><>

\bold{\rightarrow Mordancy \leftarrow}

7 0
3 years ago
Simply this plz ո • ո3
anzhelika [568]

Answer:

Answer is n^4

Step-by-step explanation:

You add the exponent when they are multiplying and have the same base

4 0
2 years ago
Read 2 more answers
Rafeeq bought a field in the form of a quadrilateral (ABCD)whose sides taken in order are respectively equal to 192m, 576m,228m,
Valentin [98]

Answer:

a. 85974 m²

b. 17,194,800 AED

c. 18,450 AED

Step-by-step explanation:

The sides of the quadrilateral are given as follows;

AB = 192 m

BC = 576 m

CD = 228 m

DA = 480 m

Length of a diagonal AC = 672 m

a. We note that the area of the quadrilateral consists of the area of the two triangles (ΔABC and ΔACD) formed on opposite sides of the diagonal

The semi-perimeter, s₁,  of ΔABC is found as follows;

s₁ = (AB + BC + AC)/2 = (192 + 576 + 672)/2 = 1440/2 = 720

The area, A₁, of ΔABC is given as follows;

Area\, of \, \Delta ABC = \sqrt{s_1\cdot (s_1 - AB)\cdot (s_1-BC)\cdot (s_1 - AC)}

Area\, of \, \Delta ABC = \sqrt{720 \times (720 - 192)\times  (720-576)\times  (720 - 672)}

Area\, of \, \Delta ABC = \sqrt{720 \times 528 \times  144 \times  48} = 6912·√(55) m²

Similarly, area, A₂, of ΔACD is given as follows;

Area\, of \, \Delta ACD= \sqrt{s_2\cdot (s_2 - AC)\cdot (s_2-CD)\cdot (s_2 - DA)}

The semi-perimeter, s₂,  of ΔABC is found as follows;

s₂ = (AC + CD + D)/2 = (672 + 228 + 480)/2 = 690 m

We therefore have;

Area\, of \, \Delta ACD = \sqrt{690 \times (690 - 672)\times  (690 -228)\times  (690 - 480)}

Area\, of \, \Delta ACD = \sqrt{690 \times 18\times  462\times  210} = \sqrt{1204988400} = 1260\cdot \sqrt{759} \ m^2

Therefore, the area of the quadrilateral ABCD = A₁ + A₂ = 6912×√(55) + 1260·√(759) = 85973.71 m² ≈ 85974 m² to the nearest meter square

b. Whereby the cost of 1 meter square land = 200 AED, we have;

Total cost of the land = 200 × 85974 = 17,194,800 AED

c. Whereby the cost of fencing 1 m = 12.50 AED, we have;

Total perimeter of the land = 576 + 192 + 480 + 228 = 1,476 m

The total cost of the fencing the land = 12.5 × 1476 = 18,450 AED

4 0
3 years ago
If arc AE = 64° and arc BD = 20°, find the measure of angle BCD.
tamaranim1 [39]
Angle mes BCD = (mes Arc AE-mes ARC BD)/2


Plug: mes BCD = (64+20)/2 = 44° (Number C)
5 0
3 years ago
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