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Temka [501]
3 years ago
6

R, S, and T represent the lengths of the three sides of a right triangle. Select the equation that represent the relationship be

tween R, S and T. (the two's are exponents)
a. R 2+ S 2= T 2

b. R 2+ T 2 = S 2

c. R 2 + R 2= S 2

d. T 2 + S 2= R 2

e. T 2- S 2= R 2
Mathematics
1 answer:
Anastaziya [24]3 years ago
5 0

Answer:

a. R 2+ S 2= T 2

Step-by-step explanation:

Is this multiple choice? If not, then I will explain my answer.

I would say that it is R² + S² = T² because, the original pythagorean theorem equation is a² + b² = c².

They are put in an alphabetical order, a, b, c.

R goes first in the alphabet, then S and T. So, that's why I say it is:

R² + S² = T²

I hope this helps! Please tell me if I'm incorrect! Have a great day may God bless you!

(Also, if you have a keyboard like mine, then you can make an exponent 2, by doing alt + 0178 )

² <-or just cut and paste this

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Answer:

a. E(x) = 3.730

b. c = 3.8475

c. 0.4308

Step-by-step explanation:

a.

Given

0 x < 3

F(x) = (x-3)/1.13, 3 < x < 4.13

1 x > 4.13

Calculating E(x)

First, we'll calculate the pdf, f(x).

f(x) is the derivative of F(x)

So, if F(x) = (x-3)/1.13

f(x) = F'(x) = 1/1.13, 3 < x < 4.13

E(x) is the integral of xf(x)

xf(x) = x * 1/1.3 = x/1.3

Integrating x/1.3

E(x) = x²/(2*1.13)

E(x) = x²/2.26 , 3 < x < 4.13

E(x) = (4.13²-3²)/2.16

E(x) = 3.730046296296296

E(x) = 3.730 (approximated)

b.

What is the value c such that P(X < c) = 0.75

First, we'll solve F(c)

F(c) = P(x<c)

F(c) = (c-3)/1.13= 0.75

c - 3 = 1.13 * 0.75

c - 3 = 0.8475

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c.

What is the probability that X falls within 0.28 minutes of its mean?

Here we'll solve for

P(3.73 - 0.28 < X < 3.73 + 0.28)

= F(3.73 + 0.28) - F(3.73 + 0.28)

= 2*0.28/1.3 = 0.430769

= 0.4308 -- Approximated

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Answer:

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