Find the sum of the interior angle measures of a 7-gon

Please help me! Im not good at this topic.

romanna [79]

Answer:

I THINK IT IS C.

Step-by-step explanation:

3 0

3 years ago

Exponential growth/decay problem 1

RUDIKE [14]

Answer:

a) growth

b) $500

c) 6% = 0.06

d) $f(x)=500(1.06)^x$

e) $595.51

Step-by-step explanation:

Part (a)

Exponential GROWTH, since interest is applied to the account each year.

Part (b)

Initial amount = $500

Part (c)

Growth factor = 6% = 0.06 (in decimal form)

Part (d)

General form of exponential growth function:

$f(x)=a(1+r)^x$

where:

a = initial amount
r = rate of growth (in decimal form)
x = time (in years)

Given:

a = 500
r = 0.06

$\implies f(x)=500(1+0.06)^x$

$\implies f(x)=500(1.06)^x$

Part (e)

when x = 3

$\begin{aligned}\implies f(3) & =500(1.06)^3\\ & = 595.51\: \sf(nearest\:hundredth)\end{aligned}$

5 0

2 years ago

An e-mail filter is planned to separate valid e-mails from spam. The word free occurs in 60% of the spam messages and only 4% of

ANEK [815]

Answer:

(a) 0.152

(b) 0.789

(c) 0.906

Step-by-step explanation:

Let's denote the events as follows:

F = The word free occurs in an email

S = The email is spam

V = The email is valid.

The information provided to us are:

The probability of the word free occurring in a spam message is, $P(F|S)=0.60$
The probability of the word free occurring in a valid message is, $P(F|V)=0.04$
The probability of spam messages is,

$P(S)=0.20$

First let's compute the probability of valid messages:

$P (V) = 1 - P(S)\\=1-0.20\\=0.80$

(a)

To compute the probability of messages that contains the word free use the rule of total probability.

The rule of total probability is:

$P(A)=P(A|B)P(B)+P(A|B^{c})P(B^{c})$

The probability that a message contains the word free is:

$P(F)=P(F|S)P(S)+P(F|V)P(V)\\=(0.60*0.20)+(0.04*0.80)\\=0.152\\$

The probability of a message containing the word free is 0.152

(b)

To compute the probability of messages that are spam given that they contain the word free use the Bayes' Theorem.

The Bayes' theorem is used to determine the probability of an event based on the fact that another event has already occurred. That is,

$P(A|B)=\frac{P(B|A)P(A)}{P(B)}$

The probability that a message is spam provided that it contains free is:

$P(S|F)=\frac{P(F|S)P(S)}{P(F)}\\=\frac{0.60*0.20}{0.152} \\=0.78947\\$

The probability that a message is spam provided that it contains free is approximately 0.789.

(c)

To compute the probability of messages that are valid given that they do not contain the word free use the Bayes' Theorem. That is,

$P(A|B)=\frac{P(B|A)P(A)}{P(B)}$

The probability that a message is valid provided that it does not contain free is:

$P(V|F^{c})=\frac{P(F^{c}|V)P(V)}{P(F^{c})} \\=\frac{(1-P(F|V))P(V)}{1-P(F)}\\=\frac{(1-0.04)*0.80}{1-0.152} \\=0.90566$

The probability that a message is valid provided that it does not contain free is approximately 0.906.

4 0

4 years ago

Please solve: -8+1 >-23

elena-14-01-66 [18.8K]

-8 + 1 = -9 and its less than

3 0

3 years ago

Read 2 more answers

In file, please answer with prooooooof :D

BigorU [14]

Answer:

B. 128 square centimeters

Step-by-step explanation:

So first make the top triangle part its own figure. By using information provided you can figure out the height of the triangle would be 3 by subtracting 11 from 14. Take 3 multiply it by the base and then 1/2 to get 18. Then find the area of the rectangle which would be 10 times 11 which is 110. Add the areas of the two parts, 110 and 18 to get 128.

6 0

3 years ago