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3 years ago

Deangelo has $7 worth of dimes and quarters in a jar. He has 7 more quarters than dimes.

Mathematics

2 answers:

Aleksandr [31]3 years ago

4 0

Deangelo has 15 dimes and 22 quarters

Hope this helps

svlad2 [7]3 years ago

3 0

D=number of dimes
q=number of quarters

let's count everything in cents
dimes are worth 10 cents
quarters are worth 25 cents

10d+25q=700
divide both sides by 5
2d+5q=140

he has 7 more quarters than dimes
q=7+d
subsitute 7+d for q in other equation

2d+5q=140
2d+5(7+d)=140
2d+35+5d=140
7d+35=140
minus 35 both sides
7d=105
divide both sides by 7
d=15

sub back

q=7+d
q=7+15
q=22

22 quarters and 15 dimes

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nydimaria [60]

Answer:

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Step-by-step explanation:

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3 years ago

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3 years ago

How can I solve ¾ - (-5/12)?

Oksana_A [137]

Answer:

$1 \frac{1}{6}$

Step-by-step explanation:

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$(\frac{3}{4}$ × $\frac{3}{3} )$ + $(\frac{5}{12}$ × $\frac{1}{1})=?$

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7/6= $1 \frac{1}{6}$

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(3×12) − (−5×4) 4×12

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Convert to a mixed number using

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1 year ago

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3 years ago

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dezoksy [38]

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3 0

3 years ago