All categories

3 years ago

What is 9 divided by 15. Steps please to help me understand

Mathematics

2 answers:

STALIN [3.7K]3 years ago

8 0

9/15=0.6

Long division can be used to do this. Simply find out how much 15 would go into 90 (or 9.0 while using long division and add you decimal)

Eva8 [605]3 years ago

4 0

9/15 becomes 90/15 but now u have a point on ur answer so it would be .6 as 15 times 6 equals 90

You might be interested in

15=3(2x+4)-3 prove x=1

kherson [118]

Answer:

X=1

Step-by-step explanation:

6x+12-3=15

6x+9=15

6x+9-9=15-9

6x=6

X=1

4 0

3 years ago

Read 2 more answers

Clare has a recipe for yellow cake. She uses 913 cups of flour to make 4 cakes. Noah will follow the same recipe. He will make c

lidiya [134]

Answer:

f/c

Step-by-step explanation:

it is bcs 913/4 and the same concept is used

7 0

3 years ago

Simplify. <img src="https://tex.z-dn.net/?f=%5Csqrt%7B15%7D" id="TexFormula1" title="\sqrt{15}" alt="\sqrt{15}" align="absmiddle

jolli1 [7]

Answer:

I think its 15.58

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

5. Simplify the expressions below by combining like terms<br> a) 4 + x + 3x + 2x - 2

zalisa [80]

Answer:

6x + 2

Explanation:

4 + -2 = 2 and x + 3x + 2x = 6x

3 0

2 years ago

a. Among a shipment of 5,000 tires, 1,000 are slightly blemished. If one purchases 10 of these tires, what is the probability th

hodyreva [135]

Answer:

<h2>See the explanation.</h2>

Step-by-step explanation:

3 or less than 3 tires among the 10 tires should be blemished.

There are some possibilities.

1000 tires are blemished, (5000 - 1000) = 4000 tires are not blemished.

From the 5000 tires, 10 tires can be chosen in $^{5000}C_{10}$ ways.

Possibility 1: <u>3 tires are blemished.</u>

Total 10 tires can be chosen with 3 blemished tires in $^{1000}C_3 \times {4000}C_7$ ways.

Possibility 2: <u>2 tires are blemished.</u>

Total 10 tires can be chosen with 2 blemished tires in $^{1000}C_2 \times ^{4000}C_8$ ways.

Possibility 3: <u>1 tires are blemished.</u>

Total 10 tires can be chosen with 1 blemished tires in $^{1000}C_1 \times^{4000}C_9$ ways.

Possibility 4: <u>No tires are blemished.</u>

Total 10 tires can be chosen with no blemished tires in $^{1000}C_0 \times^{4000}C_{10}$ ways.

Hence, the required probability is $\frac{^{1000}C_1 \times^{4000}C_9 + ^{1000}C_0 \times^{4000}C_{10} + ^{1000}C_2 \times^{4000}C_8 + ^{1000}C_3 \times^{4000}C_7}{^{5000}C_{10} }$ .

6 0

2 years ago