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3 years ago

12

tom has 28 milk chocolates and emily has 24 dark chocolates they have to divide these chocolates into small packets that each ha

ve the same number of dark chocolates and the same number of milk chocolates

2 answers:

masya89 [10]3 years ago

8 0

4 milk chocolatero need to be removed to have even amounts
24+24= 48
24 packets with 1 of each(2 count) is one possibility.
You can have less packets with more chocolates inside like 12 packets with 4 count(2 of each)
Any combination with result 48. To use al chocolatesl : 4 packets:Each packet has 6dark and 7milk choc

stealth61 [152]3 years ago

3 0

26... 24+28=52... 52÷2=26

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Any help on this?<br> Y=3x+7 <br> Y=x+1

denis23 [38]

Answer:

The answer is (x,y)=(-3,-2)

Step-by-step explanation:

I used the comparison method because I dont know what type of method you needed, sorry. The methods I know would be: the Comparison Method (what I used), the Substitution Method, Elimination Method,Inverse Matrix Method, Cramer's Rule, and the Gauss-Jordan Method.

You can also rewrite this equation to 3x-y=-7 and x-y=-1.

I'm sorry, I dont know what kind of answer you're looking for. I really hope this helps.

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3 years ago

Find the 13th term of the arithmetic sequence -3x+7, -5x+3, -7x-1, ...

oksano4ka [1.4K]

Answer:

a₁₃ = - 27x - 41

Step-by-step explanation:

The nth term of an arithmetic sequence is

$a_{n}$ = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = - 3x + 7

d = a₂ - a₁ = - 5x + 3 - (- 3x + 7)

= - 5x + 3 + 3x - 7

= - 2x - 4

Then

a₁₃ = - 3x + 7 + 12(- 2x - 4)

= - 3x + 7 - 24x - 48

= - 27x - 41

3 0

3 years ago

Here are the vertices of rectangle FROG: (-2,5),(-2,1),(6,5),(6,1). Find the perimeter of this rectangle. If you get stuck, try

ryzh [129]

Answer:

Part 1) The perimeter of rectangle is equal to 24 units

Part 2) The area of rectangle is equal to 32 square units

Step-by-step explanation:

Part 1) Find the perimeter of rectangle

we know that

The perimeter of rectangle is equal to

$P=2(L+W)$

where

L is the length of rectangle

W is the width of rectangle

we have

$F(-2,5),R(-2,1),O(6,1),G(6,5)$

Plot the figure to better understand the problem

using a graphing tool

see the attached figure

Remember that in a rectangle opposite sides are congruent and the measure of each interior angle is equal to 90 degrees

so

$FG=RO=L\\RF=OG=W$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find the distance FG

$F(-2,5),G(6,5)$

substitute the values

$d=\sqrt{(5-5)^{2}+(6+2)^{2}}$

$d=\sqrt{(0)^{2}+(8)^{2}}$

$FG=8\ units$

step 2

Find the distance RF

$R(-2,1),F(-2,5)$

substitute the values

$d=\sqrt{(5-1)^{2}+(-2+2)^{2}}$

$d=\sqrt{(4)^{2}+(0)^{2}}$

$RF=4\ units$

step 3

Find the perimeter

$P=2(L+W)$

we have

$FG=RO=L=8\ units\\RF=OG=W=4\ units$

substitute

$P=2(8+4)=24\ units$

Part 2) Find the area of rectangle FROG

we know that

The area of rectangle is equal to

$A=LW$

we have

$FG=RO=L=8\ units\\RF=OG=W=4\ units$

substitute

$A=(8)(4)=32\ units^2$

8 0

3 years ago

Im stuck on this question, Please help!

Alexxx [7]

= (x^18y^24)/(x^2y^2)

Simplified = x^16y^22

The last answer is correct (x^16y^22)

3 0

2 years ago

Please help me!!! i will gladly give brainliest :)

True [87]

Given:

ΔONP and ΔMNL.

To find:

The method and additional information that will prove ΔONP and ΔMNL similar by the AA similarity postulate?

Solution:

According to AA similarity postulate, two triangles are similar if their two corresponding angles are congruent.

In ΔONP and ΔMNL,

$\angle ONP\cong \angle MNL$ (Vertically opposite angles)

To prove ΔONP and ΔMNL similar by the AA similarity postulate, we need one more pair of corresponding congruent angles.

Using a rigid transformation, we can prove

$\angle NOP\cong \angle NML$

Since two corresponding angles are congruent in ΔONP and ΔMNL, therefore,

$\Delta ONP\sim \Delta MNL$ (AA postulate)

Therefore, the correct option is A.

8 0

2 years ago

Read 2 more answers