Given:
Tangent segment MN = 6
External segment NQ = 4
Secant segment NP =x + 4
To find:
The length of line segment PQ.
Solution:
Property of tangent and secant segment:
If a secant and a tangent intersect outside a circle, then the product of the secant segment and external segment is equal to the product of the tangent segment.
Subtract 16 from both sides.
Divide by 4 on both sides.
The length of line segment PQ is 5 units.
Angle EBD and Angle DBE are adjacent
Answer:
3003
Step-by-step explanation:
The number of differents menus containing 10 main courses that the restaurant can make if it has 15 main courses from which to chose is calculated through the combination: 15C10. The formula of the combination is: nCr = n! / ((r!) x(n - r)!)
Where r=10 and n=15
Substituting the values to the equation: 15C10 = 15! / (10!)x(10 - 5)! = 3003
Then there are 3003 different menus that a restaurant can makeif it has 15 main courses from which to choose.
If a fish grows 20 inches per 5 months, that means that the fish grows 4 inches a month (20/5).
Using this, multiply 8x4 to get 32, which is your answer.
The fish will grow 32 inches in 8 months. Hope this helps!
4|x - 1| - 7 = -3 |add 7 to both sides
4|x - 1| = 4 |divide both sides by 4
|x - 1| = 1 ⇔ x - 1 = 1 or x - 1 = -1 |add 1 to both sides
x = 2 or x = 0
Answer: B.
