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soldi70 [24.7K]
4 years ago
11

How do you solve this absolute value equatuon? 4|x - 1| - 7 = -3

Mathematics
1 answer:
MatroZZZ [7]4 years ago
3 0
4|x - 1| - 7 = -3    |add 7 to both sides

4|x - 1| = 4    |divide both sides by 4

|x - 1| = 1 ⇔ x - 1 = 1 or x - 1 = -1    |add 1 to both sides

x = 2 or x = 0

Answer: B.
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\implies {\blue {\boxed {\boxed {\purple {\sf { f(-9)= 0.48}}}}}}

\large\mathfrak{{\pmb{\underline{\orange{Step-by-step\:explanation}}{\orange{:}}}}}

f(x) =  \frac{2x + 3}{4x + 5} \\

For f(-9), put "-9" for every value of "x".

↬f( - 9) =  \frac{2( - 9) + 3}{4( - 9) + 5}\\

↬ f(-9) =  \frac{ - 18 + 3}{ - 36 + 5} \\

↬ f(-9) =  \frac{ - 15}{ - 31}\\

↬ f(-9)=  \frac{15}{31}\\

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\bold{ \green{ \star{ \red{Mystique35}}}}⋆

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