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Vlada [557]
3 years ago
10

What is the length of line segment PQ? If you can please explain, thanks.

Mathematics
2 answers:
Gnoma [55]3 years ago
7 0

Answer:

PQ=5

Step-by-step explanation:

just took test on edge 2020

nydimaria [60]3 years ago
5 0

Given:

Tangent segment MN = 6

External segment NQ = 4

Secant segment NP =x + 4

To find:

The length of line segment PQ.

Solution:

Property of tangent and secant segment:

If a secant and a tangent intersect outside a circle, then the product of the secant segment and external segment is equal to the product of the tangent segment.

\Rightarrow NQ\times NP = MN^2

\Rightarrow 4\times (x+4) = 6^2

\Rightarrow 4x+16 = 36

Subtract 16 from both sides.

\Rightarrow 4x+16-16 = 36-16

\Rightarrow 4x =20

Divide by 4 on both sides.

$\Rightarrow\frac{4x}{4}=\frac{20}{4}

\Rightarrow x = 5

The length of line segment PQ is 5 units.

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Answer:

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Step-by-step explanation:

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Since, terminal side of angle 'a' lies in quadrant 3, sine of angle 'a' will be negative.

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Similarly, terminal side of angle 'b' lies in quadrant 2, sine of angle 'b' will be  negative.

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By substituting these values in the identity,

cos(a + b) = (-\frac{1}{3})(-\frac{1}{4})-(-\frac{2\sqrt{2}}{3})(-\frac{\sqrt{15}}{4})

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Therefore, cos(a + b) = \frac{1}{12}(1-2\sqrt{30})

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