The answer is all of the students are members of the frequent visitor program.
Let x be the number of students that are members of the frequent visitor program.
Let y be the number of students that are not members of the frequent visitor program.
There are in total 19 students: x + y = 19
x students will pay $11, y students will pay $13 for the ticket. Totally, it will be $209: 11x + 13y = 209
Now, we have the system of two equations:
x + y = 19
11x + 13y = 209
____________
Use the method of substitution:
x + y = 19
⇒ x = 19 - y
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11(19-y) + 13y = 209
11·19 - 11·y + 13y = 209
209 - 11y + 13y = 209
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Rearange:
13y - 11y = 209 - 209
2y = 0
⇒ y = 0
Since y = 0, x = 19:
x + y = 19
x + 0 = 19
x = 19
This means that all of the students in the group are members of the frequent visitor program.
Prime: 2/8
Even: 6/8
Number 5: 1/8
Answer:
x = -2, y = -3
Step-by-step explanation:
Multiply eqn1 by the LCM of 1 and 6 i.e coefficients of x
We get:
<u> </u><u> </u> 6x - 54y = 150 (eqn1)
<u>6x - 5y = 3</u> (eqn2)
<u> - 49y = 147</u>
y = <u>147</u>
-49
y = -3
Substitute y in eqn2
6x - 5(-3) = 3
6x + 15 = 3
6x = -12
x = -2
2×(5^8/5^5) = 2501 have a goo day
Answer:
y=10x+50
Step-by-step explanation:
This has to be an error because this doesn't make sense this has to be B