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miv72 [106K]
3 years ago
7

Urgent number nine real URGENT

Mathematics
1 answer:
pashok25 [27]3 years ago
6 0

Answer:

the answer is b

Step-by-step explanation:

answers is pictured

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4.23 x 10 to the 4, 2 x 10 to the 3, 9.2 x 10 to the 6, 4 x 10 to the 3, 8 x 10 to the 7, and 3.2 x 10 to the 10.

Step-by-step explanation:

I will explain in the comments to this response

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Find the measure of an angle that is complementary to
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9 degrees

Step-by-step explanation:

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Talja [164]
Can you show the multiple choice one
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3 years ago
Find the perimeter of the triangle with vertices ​A(negative 2​,2​,3​), ​B(4​,negative 4​,3​), and ​C(7​,6​,4​).
gayaneshka [121]

Answer:

P\approx 28.872\,\text{units}

Step-by-step explanation:

We are given coordinates of each of the vertices of the triangle ABC, hence we can use the distance formula to find the lengths of each of the side.

the distance formula is generally written as:

r = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2+(z_1-z_2)^2}

for the side AB: A(-2,2,3) and B(4,-4,3)

AB = \sqrt{(-2-4)^2+(2-(-4))^2+(3-3)^2}

AB = \sqrt{(-6)^2+(6)^2+(3-3)^2}

AB = \sqrt{72}

for the side BC: B(4,-4,3) and C(7,6,4)

BC = \sqrt{(4-7)^2+((-4)-6)^2+(3-4)^2}

BC = \sqrt{110}

for the side CA: C(7,6,4) and A(-2,2,3)

CA = \sqrt{(7-(-2))^2+(6-2)^2+(4-3)^2}

CA = \sqrt{98}

Now we all the sidelengths:

to find the perimeter we need to just sum the three side lengths:

P = AB + BC + CA

P = \sqrt{72} + \sqrt{110} + \sqrt{98}

P\approx 28.872\,\text{units}

this is the perimeter of triangle ABC

6 0
4 years ago
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