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mestny [16]
3 years ago
12

What amount should Andy write for the balance on January 30?

Mathematics
1 answer:
LenKa [72]3 years ago
4 0
104.47 + 402.71 = 507.18 <===
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Mathematical Statistics with Applications Help Homework
Mars2501 [29]

7.43: Let X denote the random variable for height and \overline X for the sample mean. Then if \mu is the mean of

So the probability that the difference between the sample and population means does not exceed 0.5 inch is

P(|\overline X-\mu|\le0.5) = P\left(\left|\dfrac{\overline X-\mu}{0.25}\right|\le\dfrac{0.5}{0.25}\right) = P(|Z|\le 2) \approx \boxed{0.95}

per the empirical or 68/95/99.7 rule.

7.44: For a sample of size <em>n</em>, the sample standard deviation would be \frac{2.5}{\sqrt n}. We want to find <em>n</em> such that

P(|\overline X-\mu| < 0.4) = 0.95

Comparing to the equation from the previous part, this means we would need

\dfrac{0.4}{\frac{2.5}{\sqrt{n}}} = 0.16\sqrt n = 2 \implies \sqrt n = 12.5 \implies n = 156.25

so a sample of at least 157 men would be sufficient.

7 0
3 years ago
EASY BRAINLIEST PLEASE HELP!!
Irina-Kira [14]

Answer:

A rhombus

A rhombus is a flat-shaped quadrilateral-

3 0
2 years ago
Read 2 more answers
a metal worker has a metal alloy that is 20% copper, and another metal alloy that is 60% copper. How many kilograms (kg) of each
emmainna [20.7K]

Let X = the 29% alloy and Y = the 60% alloy.

They want a total of 80kg, so you have X +Y = 80

Rewrite that to get X = 80-Y


You also want 0.20X + 0.60Y = 0.52(80)

Replace X with 80-y:

0.20(80-y) + 0.60y = 0.52(80)

Simplify:

16 - 0.20y + 0.60y = 41.6

Combine like terms:

16 +0.40y = 41.6

Subtract 16 from each side:

0.40y = 25.6

Divide both sides by 0.40

y = 25.6 / 0.40

y = 64


Now you have Y replace y with 80 in X = 80-Y

X = 80 - 64

X = 16

They need 64 Kg of the 60% alloy and 16 Kg of the 20% alloy.


5 0
2 years ago
Ratio of blue to green sweets is 2:7 Ration of green to red sweets is 3:1 There are less than 140 sweets in the bag Greatest amo
UNO [17]

Answer:

35 sweets

Step-by-step explanation:

Ratio of blue to green sweets is 2:7 Ration of green to red sweets is 3:1 There are less than 140 sweets in the bag Greatest amount of red sweets

Ration of green to red sweets is 3:1

Total Proportion = 3 + 1 = 4

Total number of sweet = > 140 sweets

The greatest amount of red sweets =

1/4 × 140 = 35 sweets

8 0
2 years ago
Pls help ME PLSSSSS!!!!!!
Scilla [17]

(a) the interquartile range

Would be 72 - 88

the med would be 84  

(b) I may be wrong but my guess would be

88% above all the seasons because the scale that was shown went to 100 and that would cause each win to be 1%. the bottom would have to equal out to 12% because that is what we would need to make it equal out to 100.

Hope this helps

8 0
3 years ago
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