7.43: Let 
denote the random variable for height and 
for the sample mean. Then if 
is the mean of
So the probability that the difference between the sample and population means does not exceed 0.5 inch is
per the empirical or 68/95/99.7 rule.
7.44: For a sample of size <em>n</em>, the sample standard deviation would be 
. We want to find <em>n</em> such that
Comparing to the equation from the previous part, this means we would need
so a sample of at least 157 men would be sufficient.
Answer:
A rhombus
A rhombus is a flat-shaped quadrilateral-
Let X = the 29% alloy and Y = the 60% alloy.
They want a total of 80kg, so you have X +Y = 80
Rewrite that to get X = 80-Y
You also want 0.20X + 0.60Y = 0.52(80)
Replace X with 80-y:
0.20(80-y) + 0.60y = 0.52(80)
Simplify:
16 - 0.20y + 0.60y = 41.6
Combine like terms:
16 +0.40y = 41.6
Subtract 16 from each side:
0.40y = 25.6
Divide both sides by 0.40
y = 25.6 / 0.40
y = 64
Now you have Y replace y with 80 in X = 80-Y
X = 80 - 64
X = 16
They need 64 Kg of the 60% alloy and 16 Kg of the 20% alloy.
Answer:
35 sweets
Step-by-step explanation:
Ratio of blue to green sweets is 2:7 Ration of green to red sweets is 3:1 There are less than 140 sweets in the bag Greatest amount of red sweets
Ration of green to red sweets is 3:1
Total Proportion = 3 + 1 = 4
Total number of sweet = > 140 sweets
The greatest amount of red sweets =
1/4 × 140 = 35 sweets
(a) the interquartile range
Would be 72 - 88
the med would be 84
(b) I may be wrong but my guess would be
88% above all the seasons because the scale that was shown went to 100 and that would cause each win to be 1%. the bottom would have to equal out to 12% because that is what we would need to make it equal out to 100.
Hope this helps
