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3 years ago

If LP = 15 and PR = 9, find LR. Explain.

Mathematics

1 answer:

Rudiy273 years ago

5 0

Answer:

Step-by-step explanation:

LP = 15 on one side

LR= 9 on the other side

____________________|____________|

P L R

add them and PR is 24

15+9= 24

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PLEASE HELP FAST!!!

Rus_ich [418]

$\\ \sf\longmapsto 3s-5+2s+25=170$

$\\ \sf\longmapsto 5s+20=170$

$\\ \sf\longmapsto 5s=170-20$

$\\ \sf\longmapsto 5s=150$

$\\ \sf\longmapsto s=30$

m<GHZ=3(30)-5=90-5=85
m<ZHI=2(30)+25=60+25=85

4 0

3 years ago

your car weighs 7,630 pounds. There is a road safety fee for cars. you fee is $28 plus $0.023 per pound. What is the fee for you

rusak2 [61]

Answer:

Step-by-step explanation:

7630 x .023 = 175.49

175.49 + 28 = $203.49

3 0

3 years ago

Can someone please help...

Karolina [17]

Answer:

See below for explanation of the examples.

Step-by-step explanation:

Left example

It is an exercise in addition, i.e. 48+122=170, the answer is written in the bottom box.

Right example

It is an exercise in subtraction, i.e. 8 1/2 - 3 1/2 = 5

The answer is written in the bottom box.

There is no indication though as to when to do the addition, and when to do the subtraction. Perhaps it would be shown in the rest of the page (not shown).

8 0

3 years ago

Write the numeral 0.0284 × 10^4 in scientific notation. A. 28.4 × 101 B. 0.284 × 103 C. 2.84 × 102 D. 284

Thepotemich [5.8K]

Answer:

2.84×10²

Step-by-step explanation:

0.0284×10⁴

Move the decimal point 4 places to the right.

284

Now write in scientific notation by moving the decimal point 2 places to the left, behind the 2.

2.84×10²

7 0

3 years ago

Find the vertical and horizontal asymptotes, domain, range, and roots of f (x) = -1 / x-3 +2.

gladu [14]

Answer:

Vertical asymptote: $x=3$

Horizontal asymptote: $f(x) =2$

Domain of f(x) is all real numbers except 3.

Range of f(x) is all real numbers except 2.

Step-by-step explanation:

Given:

Function:

$f (x) = -\dfrac{1 }{ x-3} +2$

One root, $x = 3.5$

To find:

Vertical and horizontal asymptote, domain, range and roots of f(x).

Solution:

First of all, let us find the roots of f(x).

<em>Roots of f(x) means the value of x where f(x) = 0</em>

$0= -\dfrac{1 }{ x-3} +2\\\Rightarrow 2= \dfrac{1 }{ x-3}\\\Rightarrow 2x-2 \times 3=1\\\Rightarrow 2x=7\\\Rightarrow x = 3.5$

One root, $x = 3.5$

Domain of f(x) i.e. the values that we give as input to the function and there is a value of f(x) defined for it.

For x = 3, the value of f(x) $\rightarrow \infty$

For all, other values of $x$ , $f(x)$ is defined.

Hence, Domain of f(x) is all real numbers except 3.

Range of f(x) i.e. the values that are possible output of the function.

f(x) = 2 is not possible in this case because something is subtracted from 2. That something is $\frac{1}{x-3}$ .

Hence, Range of f(x) is all real numbers except 2.

Vertical Asymptote is the value of x, where value of f(x) $\rightarrow \infty$ .

$-\dfrac{1 }{ x-3} +2 \rightarrow \infty$

It is possible only when

$x-3=0\\\Rightarrow x=3$

$\therefore$ vertical asymptote: $x=3$

Horizontal Asymptote is the value of f(x) , where value of x $\rightarrow \infty$ .

$x\rightarrow \infty \Rightarrow \dfrac{1 }{ x-3} \rightarrow 0\\\therefore f(x) =-0+2 \\\Rightarrow f(x) =2$

$\therefore$ Horizontal asymptote: $f(x) =2$

Please refer to the graph of given function as shown in the attached image.

5 0

3 years ago