Answer:
There are 60 monkeys in the Zoo
Step-by-step explanation:
In this question, we are asked to calculate the number of monkeys in a Zoo given some information to use.
Let’s have the total number of monkeys be m.
60% are going monkeys. This means number of young monkeys is 0.6m.
The number of baby and old monkeys is obviously 0.4m.
Ratio of baby to old monkeys is 3:1. This means if we splitter 0.4m into 4, number of baby monkeys is 0.3m while number of old monkeys is 0.1m
Now, subtracting the number of baby monkeys from young monkeys give a total of 18 monkeys.
Let’s project this mathematically;
This means ;
0.6m - 0.3m = 18
0.3m = 18
m = 18/0.3
m = 60
There are 60 monkeys in the zoo
Answer:
-3.69
Step-by-step explanation:
Exponential equations can be solved by taking Ln (natural logarithm) of both sides. The rule we need to know is:
![Ln(a^b)=bLn(a)](https://tex.z-dn.net/?f=Ln%28a%5Eb%29%3DbLn%28a%29)
Now lets work out this problem:
![16^{2x+3}=13^{x-1}\\Ln(16^{2x+3})=Ln(13^{x-1})\\(2x+3)Ln(16)=(x-1)Ln(13)](https://tex.z-dn.net/?f=16%5E%7B2x%2B3%7D%3D13%5E%7Bx-1%7D%5C%5CLn%2816%5E%7B2x%2B3%7D%29%3DLn%2813%5E%7Bx-1%7D%29%5C%5C%282x%2B3%29Ln%2816%29%3D%28x-1%29Ln%2813%29)
Using calculator, we take the values of Ln 16 and Ln 13 as:
Ln 16 = 2.7726
Ln 13 = 2.5649
Now, we can solve for x:
![(2x+3)Ln(16)=(x-1)Ln(13)\\(2x+3)2.7726=(x-1)2.5649\\5.5452x+8.3178=2.5649x-2.5649\\2.9803x=-10.8827\\x=-3.69](https://tex.z-dn.net/?f=%282x%2B3%29Ln%2816%29%3D%28x-1%29Ln%2813%29%5C%5C%282x%2B3%292.7726%3D%28x-1%292.5649%5C%5C5.5452x%2B8.3178%3D2.5649x-2.5649%5C%5C2.9803x%3D-10.8827%5C%5Cx%3D-3.69)
x is -3.69 (rounded to 2 decimal places)
Answer:
The mean depends on the no. of family members but the question hasn't mentioned it. So I have no idea what to do with this.
3c^5
The greatest number that goes into both 6 and 15 is 3, and both values of c have at least c^5.
hope this helps :)