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Pepsi [2]
3 years ago
6

Find the length of the base of a square pyramid if the volume is 128 cubic inches and has a height of 6 inches

Mathematics
1 answer:
Len [333]3 years ago
6 0

Answer: a = 8

Step-by-step explanation:

Volume of a square based pyramid is given as

\frac{a^{2}h }{3} .

where a is the length of the side and h is the height.

Substituting into the formula , we have

V = \frac{a^{2}h }{3}

128 = a^{2}h /3

384= a^{2} X 6

Divide through by 6

384/6 = a^{2}

64 = a^{2}

Therefore :

a = \sqrt{\frac{64}{1} }

a = 8

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Write an equation in standard form passing through the points (-2, 0) and (-3, -1). I know the answer to the question, but I do
g100num [7]

Answer:

y - x = 2

Step-by-step explanation:

Given

Points (-2,0) and (-3,-1)

Required

Equation of Line

The first step is to determine the slope of the line; using the following formula

m = \frac{y_2 - y_1}{x_2 - x_1}

Where\ (x_1,y_1) = (-2,0)\ and\ (x_2,y_2) = (-3,-1)

m = \frac{y_2 - y_1}{x_2 - x_1} becomes

m = \frac{-1 -0}{-3 - (-2)}

m = \frac{-1}{-3 +2}

m = \frac{-1}{-1}

m = 1

The next is to determine the equation of the line using any of the points

The formula is as thus;

m = \frac{y - y_1}{x - x_1}\ or\  m = \frac{y - y_2}{x - x_2}

Using m = \frac{y - y_1}{x - x_1}

Where\ (x_1,y_1) = (-2,0)\ and\ m =1

1  = \frac{y-0}{x - (-2)}

1  = \frac{y-0}{x +2}

1  = \frac{y}{x +2}

Multiply both sides by x + 2

(x+2)*1  = \frac{y}{x +2} * (x+2)

(x+2)*1  = y

x+2  = y

y = x + 2

Subtract x from both sides

y - x = x - x +2

y - x = 2

Hence, the equation of the line in standard form is y - x = 2

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