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kiruha [24]
3 years ago
12

Simplify: 4x^2+36/4x•1/5x

Mathematics
2 answers:
zysi [14]3 years ago
8 0

Answer:

Step-by-step explanation:

The given equation is:

\frac{4x^2+36}{4x}{\times}\frac{1}{5x}

On solving the above equation, we get

=\frac{4x^2+36}{(4x)(5x)}

=\frac{4(x^2+9)}{(4x)(5x)}

=\frac{x^2+9}{(x)(5x)}

=\frac{x^2+9}{(5x^2)}

which is the required simplified form.

Thus, the simplified form of the given equation \frac{4x^2+36}{4x}{\times}\frac{1}{5x} is \frac{x^2+9}{(5x^2)}.

user100 [1]3 years ago
3 0
\frac{4x^2+36}{4x}* \frac{1}{5x}  = \frac{4(x^2+9)}{20x^2} = \frac{x^2+9}{5x^2}
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Given that:

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Given f(x) = 1/2x - 5, find f^-1(x) a. f^-1 (x) = -2x+10 b. f^-1(x) = 2x+5 c. f^-1(x) = 2x-10 d. f^-1(x) = 2x+10...

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2 years ago
Solve This Using The Quadratic Formula: 3x^2+9x-6=0
aivan3 [116]
<h3>Therefore either  x = \frac{-3+\sqrt{17}}{2}    or,  x = \frac{-3-\sqrt{17}}{2}</h3>

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