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answer : option C
Lets find the number of zeros by factoring
Group first two terms and last two terms
Factor out GCF from each group
Now we set each factor =0 and solve for x
0 = (x^2-8) and (x + 1)=0
and x = -1
and x= -1
So we have three real zeros
The function has three real zeros. The graph of the function intersects the x-axis at exactly three locations.