Answer:
8x(10)^9 - 2 x (10)^1
1x(10)^3 - 9 x (10)^2
Step-by-step explanation:
3.1 X (10)^4- 6.5 X (10)^2
= 31000- 650
= 30,350
For greater number
_x10^blank - _ x 10^_
8x(10)^9 - 2 x (10)^1 ( we use 9 as the power because greater number used as power gives the bigger number and the next smaller number 8 as base. Similarly we use smaller number for power to get a smaller for the greatest difference)
= 8,000,000,000 -20
= 7,999,999,980
For smaller number
_x10^blank - _ x 10^_
1x(10)^3 - 9 x (10)^2 ( we use 3 as the power because smaller number used as power gives the smaller number and the next smallest number 1 as base. Similarly we use next smaller number for power to get the next smaller for the smallest difference)
= 1000- 900
= 100
We fill in the blanks keeping in mind that we do not have to repeat the numbers from 1-9 and also the numbers should have such an arrangement that they show the smallest and largest possible differences.
We have to determine the complete factored form of the given polynomial
.
Let x= -1 in the given polynomial.
So, 
So, by factor theorem
(x+1) is a factor of the given polynomial.
So, dividing the given polynomial by (x+1), we get quotient as
.
So,
= (x+1)
.
= 
=![(x+1)[ 2x(3x-5)-3(3x-5)]](https://tex.z-dn.net/?f=%28x%2B1%29%5B%202x%283x-5%29-3%283x-5%29%5D)
=
is the completely factored form of the given polynomial.
Option D is the correct answer.
Answer:
About 30 if you want it really specific 29.3
Take 1,760 and divide by 60 which is 29.3
Answer:
-10x-7y hope this helps yous.
Answer:
the probability that all tomatoes are sold is 0.919 (91.9%)
Step-by-step explanation:
since the random variable X= number of tomatoes that are demanded, is normally distributed we can make the standard random variable Z such that:
Z=(X-μ)/σ = (83 - 125)/30 = -1.4
where μ= expected value of X= mean of X (since X is normally distributed) , σ=standard deviation of X
then all tomatoes are sold if the demand surpasses 83 tomatos , therefore
P(X>83) = P(Z>-1.4) = 1- P(Z≤-1.4)
from tables of standard normal distribution →P(Z≤-1.4)=0.081 , therefore
P(X>83) = 1- P(Z≤-1.4) = 1 - 0.081 = 0.919 (91.9%)
thus the probability that all tomatoes are sold is 0.919 (91.9%)