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olga_2 [115]
3 years ago
7

I need bro with this problem

Mathematics
2 answers:
aliina [53]3 years ago
4 0

Answer:

what is the question ????

laiz [17]3 years ago
3 0
What question I don’t see no question here
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Sarah downloaded two apps which were 7.48 kb total. If one app was 4.78 kb, how big was the other app?
Keith_Richards [23]

Answer:

2.7 kb

Step-by-step explanation:

Total kb = 7.48

Total apps = 2

one app = 4.78

another app = x

> 4.78 + x = 7.48

x = 7.48 – 4.78

= 2.7 kb

3 0
3 years ago
Find the area of a triangle with a base of 9 feet and hypotenuse length of 13 feet​
iris [78.8K]

Answer:

42.21 ft^2

Step-by-step explanation:

The formula: A=1 /2b √ c2﹣b2

c=hypotenuse

b=base

8 0
3 years ago
Which answers are equivalent to ? Choose all answers that are correct. A. 0.08 B. 8% C. 0.32 D. 32%
Llana [10]
A and B are equivalent and C and D are equivalent

4 0
4 years ago
Read 2 more answers
If the greatest value of n is 8, which inequality best shows all the possible values of n? (5 points) n < 8 n ≤ 8 n > 8 n
hjlf

Answer:

Step-by-step explanation:

"the greatest value of n is 8" is signified by n ≤ 8.

This is a set, and also an inequality.

4 0
4 years ago
A consumer products company is formulating a new shampoo and is interested in foam height (in millimeters). Foam height is appro
Pavel [41]

Answer:

The answers to the questions are

(a) P = 0.0176

(b)  P = 0.5

(c)  P = 0.0571

Step-by-step explanation:

The P value is the calculated probability of obtaining extreme reults which are as extreme as observed res ult when the study null hypothesis H₀ is true

The p value is given by

P (\overline{\rm x} = 185 when μ = 175)

z =  \frac{ \overline { \rm x} -\mu}{\sigma /\sqrt{n} }

z(\overline { \rm x} = 185)  = \frac{ 185 -175}{20/\sqrt{10} } = 1.5811

Therefore the P (\overline{\rm x} = 185 when μ = 175) =  P(z = 1.5811)  

    0.94295

The probability density function is

f(x) = \frac{1}{\sigma\sqrt{2\pi } } e^{-\frac{1}{2}(\frac{x-\mu}{\sigma} )^2 } Therefore the probability is

f(x) = \frac{1}{20\sqrt{2\pi } } e^{-\frac{1}{2}(\frac{185-175}{20} )^2 } = 0.0176  

b) The type II error is given by

β = P(type II error) = P(Fail to reject the null hypothesis when it is false)

Therefore

β = P (\overline { \rm x} < 185 when μ = 185)

P(\frac{ \overline { \rm x} -\mu}{\sigma /\sqrt{n} }, which gives

P(z<0) and β = 0.5

(c) For true mean foam height of 195 mm we have

β = P (\overline { \rm x} < 185 when μ = 195)

and P(\frac{ \overline { \rm x} -\mu}{\sigma /\sqrt{n} }

Which gives P(z < -1.58)

From z table the probability is       β = 0.0571

3 0
3 years ago
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