Answer:
5
Step-by-step explanation:
Since we have not instructed to follow any kind of rule dividing, we can write in any form. Let's calculate it using fraction
We can multiply both the nominator and denominator with 100
The answer is 5.
We can also solve it as a division of fractions:
Answer:
Step-by-step explanation:
A) 5x - 7 = 5x becomes -7 = 0 if 5x is subtracted from both sides. This result is never true, so NO SOLUTION
B)3x−9=3(x−3) Performing the indicated multiplication, we get
3x - 9 = 3x - 9. This is always true, so there are INFINITELY MANY SOLUTIONS
C)2x−6=−2(x−3) Performing the indicated multiplication, we get
2x - 6 = -2x + 6. Adding 2x - 6 to both sides results in
4x - 12 = 0, or 4x = 12. Thus, the solution is x = 3. ONE SOLUTION
D)2x+6−5x=−3(x This equation is incomplete
We know that
If the scalar product of two vectors<span> is zero, both vectors are </span><span>orthogonal
</span><span>A. (-2,5)
</span>(-2,5)*(1,5)-------> -2*1+5*5=23-----------> <span>are not orthogonal
</span><span>B. (10,-2)
</span>(10,-2)*(1,5)-------> 10*1-2*5=0-----------> are orthogonal
<span>C. (-1,-5)
</span>(-1,-5)*(1,5)-------> -1*1-5*5=-26-----------> are not orthogonal
<span>D. (-5,1)
</span>(-5,1)*(1,5)-------> -5*1+1*5=0-----------> are orthogonal
the answer is
B. (10,-2) and D. (-5,1) are orthogonal to (1,5)
Let's actually find the roots, using the quadratic formula:
<span>p(x)=x^2+x+3 gives us a=1, b=1 and c=3.
-1 plus or minus sqrt(1^2-4(1)(3))
Then x = -----------------------------------------------
2
The discriminant here is negative, so the roots x will be complex:
-1 plus or minus sqrt(-11) -1 plus or minus i*sqrt(11)
x = ---------------------------------- = -------------------------------------
2 2
These are irrational roots; they cannot be expressed as the ratios of integers.</span>
