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3 years ago

What is the y-intercept of 2g(x)+3x=6?

Mathematics

1 answer:

umka21 [38]3 years ago

8 0

The y-intercept is basically the value of the output of the function, g(x), when x=0.

Let's replace g(x) with the variable y to make this look a bit simpler.

2y + 3x = 6

Now, we enter the value of x=0 to get the y-intercept.

2y + 0 = 6

2y = 6

Divide both sides by 2

y = 3

The value of y is 3. Now enter the values of x=0 and y=3 into point-form (x,y) to get (0,3). You should know which answer choice to choose now.

Have an awesome day!

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Slader the internal revenue service claims it takes an average of 3.7 hours to complete a 1040 tax form, assuming th4e time to c

Vitek1552 [10]

Answer:

0.9953, 3.3629<x<4.0371

Step-by-step explanation:

Given that slader the internal revenue service claims it takes an average of 3.7 hours to complete a 1040 tax form, assuming th4e time to complete the form is normally distributed witha standard devait of the 30 minutes:

If X represents the time to complete then

X is N(3.7, 0.5) (we convert into uniform units in hours)

a) percent of people would you expect to complete the form in less than 5 hours

= $100*P(x$

b) P(b<x<c) = 0.50

we find that here

c = 4.0371 and

b = 3.3629

Interval would be

$(3.3629, 4.0371)$

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3 years ago

(7x-3) ( 11y+5) what’s the value of x

timofeeve [1]

Answer:

7x - 3 = 60

7x = 63

x = 9

if you need to find for y

11y + 5 = 60

11y = 55

y = 5

Step-by-step explanation:

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3 years ago

How do i get a better grade if i'm failing

stellarik [79]

Ask for extra credit.

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3 years ago

Read 2 more answers

Two buses leave towns 304 miles apart at the same time and travel toward each other. One bus travels 14 mih slower than the othe

8090 [49]

Answer:

The faster bus moves at 83mi/h and the slower one moves at 69mi/h.

Step-by-step explanation:

Let's define:

R₁ = rate of bus 1, this is the faster one.

R₂ = rate of bus 2, this is the slower one.

We know that one bus travels 14mi/h slower, then:

R₂ = R₁ - 14mi/h.

Now we know that:

Distance = Speed*Time.

If we add the distances that both busses travel in 2 hours, it should be equal to the initial distance between the buses, then:

R₁*2h + R₂*2h = 304 mi

Then we have the two equations:

R₂ = R₁ - 14mi/h

R₁*2h + R₂*2h = 304 mi

The first step is to replace the first equation in the second one, to get:

R₁*2h + (R₁ - 14mi/h)*2h = 304 mi

And now we can solve this for R₁.

R₁*2h + R₁*2h - 14mi/h*2h = 304 mi

R₁*4h - 28mi = 304mi

R₁*4h = 304mi + 28mi = 332mi

R₁ = 332mi/4h = 83mi/h

The faster bus moves at 83mi/h

And we know that the slower one moves at 14mi/h slower than this, then:

R₂ = R₁ - 14mi/h = 83mi/h - 14mi/h = 69 mi/h

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3 years ago

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nadya68 [22]

Answer:

its A

Step-by-step explanation:

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3 years ago