Answer:
63%
Step-by-step explanation:
<em>From the question, we aim to find the percent increase in the tuition</em>
Given data
initial cost= $99 per credit hour
Final cost= $268 per credit hour
% increase= (Final - initial )/initial *100
substitute
% increase= (268- 99 )/268 *100
% increase= 169 /268 *100
% increase= 0.630*100
% increase= 63%
Hence the increase in the tuition from 1990 to 2003 is 63%
6 under par is written as -6
2 over par is written as 2
even par is written as 0
even par is written as 0
Total score: add all the numbers together:
-6 + 2 + 0 + 0 = -4 ( 4 under par).
Formula= (y2-y1)/ (x2-x1)
(-5 - -1) / (-2 - -4)
(-4) / (2) = -2
q8 is C
(-3 - -3) / (8 - 4)
(0) / (4) = 0
q12 is D
-6.5 which in your answer choices is a
<h3>✽ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ✽</h3>
➷ It would cross at (0, -1) or just -1
y = mx + c
The 'c' value in the equation is the y intercept
<h3><u>
✽</u></h3>
➶ Hope This Helps You!
➶ Good Luck (:
➶ Have A Great Day ^-^
↬ ʜᴀɴɴᴀʜ ♡
