What types of solutions does this equation have

Fake Question So It Doesn't Get Taken Down (What is the gemological answer for 5.87 x 7?) Real Question: Whats something i could

dsp73

Answer:

dependes tell me what your in to

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

A. Renard let’s t= the number of taffy bags and c= the number of Carmel bags. Help him write two equations to represent the info

vlabodo [156]

Answer:

20 taffy bags and 15 caramel candy bags

Step-by-step explanation:

Given:

t = the number of taffy bags
c = the number of caramel bags
Number of taffy's are 5 more than caramel bags
Taffy bags weigh 8 ounces and caramel bags weigh 16 ounces
Total weight is 400 ounces

Equations:

t = c + 5 (the difference in number of bags)
8t + 16c = 400 (the weight of the bags)

Simplify the second equation by dividing all terms by 8:

t + 2c = 50

Substitute t and solve for c:

c + 5 + 2c = 50
3c = 50 - 5
3c = 45
c = 45/3
c = 15

Find the value of t:

t = 15 + 5 = 20

Answer:

20 taffy bags and 15 caramel candy bags

7 0

3 years ago

A high school principal wishes to estimate how well his students are doing in math. Using 40 randomly chosen tests, he finds tha

ollegr [7]

Answer:

99% confidence interval for the population proportion of passing test scores is [0.5986 , 0.9414].

Step-by-step explanation:

We are given that a high school principal wishes to estimate how well his students are doing in math.

Using 40 randomly chosen tests, he finds that 77% of them received a passing grade.

Firstly, the pivotal quantity for 99% confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of students received a passing grade = 77%

n = sample of tests = 40

p = population proportion

Here for constructing 99% confidence interval we have used One-sample z proportion test statistics.

So, 99% confidence interval for the population proportion, p is ;

P(-2.5758 < N(0,1) < 2.5758) = 0.99 {As the critical value of z at 0.5%

level of significance are -2.5758 & 2.5758}

P(-2.5758 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 2.5758) = 0.99

P( $-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.99

P( $\hat p-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.99

99% confidence interval for p = [ $\hat p-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.77-2.5758 \times {\sqrt{\frac{0.77(1-0.77)}{40} } }$ , $0.77+2.5758 \times {\sqrt{\frac{0.77(1-0.77)}{40} } }$ ]

= [0.5986 , 0.9414]

Therefore, 99% confidence interval for the population proportion of passing test scores is [0.5986 , 0.9414].

Lower bound of interval = 0.5986

Upper bound of interval = 0.9414

6 0

3 years ago

Which of the following equations is of a parabola with a vertex at (0, -5)

Harlamova29_29 [7]

The x, which is zero in this case will always be the number that goes on the inside of the equation, so far you have y=(x+0)^2 or y=x^2.

The y, which is negative will go on the end of the equation. So you get y=x^2-5

The equation is y=x^2-5 or C if it is multiple choice

4 0

3 years ago

Read 2 more answers

An artist is painting the outside of the box shown below. The top and bottom will NOT be painted. What is the total surface area

Montano1993 [528]

Answer:

15 square feet

Step-by-step explanation:

Multiply 1.5 by 3 which equals 4.5

Multiply 1.5 by 2 which equals 3

Add the above answers (4.5 plus 3)

Then multiply by 2 (7.5 times 2)

It equals 15

I hope this helps and that this is the right problem. There is no picture shown but I just did this problem for someone else so I thought I would take a shot at it :)

3 0

3 years ago