Answer:
1.5
Step-by-step explanation:
set x = 6
and x less than four time of 6
it may mean 6÷4
6÷4 = 1.5 #
Answer:
small=15 large=40
Step-by-step explanation:
x=large box
y=small box
55 = x + y
50x + 55y = 2825
50x + 55( 55 - x) = 2825
50x + 3025 - 55x = 2825
0 = 55x - 50 x + 2825 - 3025
0 = 5x - 200
200 = 5x
x=40
y = 15
<h3>
Answers: x = -17 and x = 64</h3>
====================================================
Explanation
Consider three scenarios:
- A) The value of x is the smallest of the set (aka the min)
- B) The value of x is the largest of the set (aka the max)
- C) The value of x is neither the min, nor the max. So 8 < x < 39.
These scenarios cover all the possible cases of what x could be. It's either the min, the max, or somewhere in between the min and max.
--------------------
We'll start with scenario A.
If x is the min, then that must mean 39 is the max as it's the largest of the set {18, 36, 16, 39, 27, 8, 34}
The range is 56, so,
range = max - min
56 = 39 - x
56+x= 39
x = 39-56
x = -17 which is one possible answer
--------------------
If instead we go with scenario B, then x is the max and 8 is the min
range = max - min
56 = x - 8
56+8 = x
64 = x
x = 64 is the other possible answer
--------------------
Lastly, let's consider scenario C. If x is not the min or the max, then it's somewhere between the min 8 and max 39. in short, 8 < x < 39.
Note that range = max - min = 39-8 = 31 which is not the range of 56 that we want. So there's no way scenario C can be possible here.
Answer: Box3 has 120 oranges.
Box1 has 150 oranges.
Box has 130 oranges.
Step-by-step explanation:
I will answer this in English.
The question says:
3 boxes have 400 oranges.
The first one has 20 more than the second and 30 more than the third.
So we have 3 equations:
box1 + box2 + box3 = 400
box1 = box2 + 20
box1 = box3 + 30
Now, we can take the variable box1 in the third equation and replace it on the other two.
box3 + 30 + box2 + box3 = 400
box3 + 30 = box2 + 20
Now we can isolate one of the variables in the second equation, let's isolate box2.
box2 = box3 + 30 - 20 = box3 + 10
now we can replace it in the other equation:
box3 + 30 + box2 + box3 = 400
box3 + 30 + box3 + 10 + box3 = 400
3*box3 + 40 = 400
3*box3 = 400 - 40 = 360
box3 = 360/3 = 120.
Box3 has 120 oranges.
Box1 has 120 + 30 = 150 oranges.
Box has 150 - 20 = 130 oranges.
