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3 years ago

Find the volume of the rectangular prism.

Mathematics

1 answer:

gavmur [86]3 years ago

5 0

Answer:

The answer is C, 281.25 cubic feet.

Step-by-step explanation:

First, you need to multiply all three sides of the rectangular prism.

10x4.5=45

45x6.25=281.25

So the answer is 281.25

Hope this helps!

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Answer:

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Kharon needs to write 3 book reports with b pages and 3 science reports with s pages during the school year. Write an algebraic

aalyn [17]

Answer:

3b+3s

Step-by-step explanation:

According to the statement, Kharon needs to write 3 book reports with b pages. This means that he has 3 books and each of them has b amount of pages which you can express as b+b+b that is equal to 3b. Also, he has 3 science reports with s pages which is 3s. In order to find the total number of pages, you have to add up 3b plus 3s. According to this, the algebraic expression for the total number of pages Kharon will need to write is: 3b+3s.

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3 years ago

Can someone please help me with my maths question

DIA [1.3K]

Answer:

$a. \ \dfrac{625 \cdot m}{27 \cdot n^{11}}$

$b. \ \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

Step-by-step explanation:

The question relates with rules of indices

(a) The give expression is presented as follows;

$\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}$

By expanding the expression, we get;

$\dfrac{m^3 \times n^{-8} \times 5^4 \times m^4}{\left 3^3 \times m^6 \times n^3}$

Collecting like terms gives;

$\dfrac{m^{(3 + 4 - 6)} \times 5^4}{ 3^3 \times n^{3 + 8}} = \dfrac{625 \cdot m}{27 \cdot n^{11}}$

$\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}= \dfrac{625 \cdot m}{27 \cdot n^{11}}$

(b) The given expression is presented as follows;

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \div (x \cdot y^n)^4$

Therefore, we get;

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n}$

Collecting like terms gives;

$x^{3 \cdot m + 2 - 4} \times \left (y^{3 \cdot n - 3 -4 \cdot n}} \right ) = x^{3 \cdot m - 2} \times \left (y^{ - 3 -n}} \right ) = x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right )$