The base of log is 10. So raising both sides to 10, we get:
S, rounding of to nearest hundredth, the value of x in the equation 0.94 = log(x) comes out to be
8.71.
We have a sample of 28 data points. The sample mean is 30.0 and the sample standard deviation is 2.40. The confidence level required is 98%. Then, we calculate α by:
The confidence interval for the population mean, given the sample mean μ and the sample standard deviation σ, can be calculated as:
![CI(\mu)=\lbrack x-Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}},x+Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}}\rbrack](https://tex.z-dn.net/?f=CI%28%5Cmu%29%3D%5Clbrack%20x-Z_%7B1-%5Cfrac%7B%5Calpha%7D%7B2%7D%7D%5Ccdot%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%5B%5D%7Bn%7D%7D%2Cx%2BZ_%7B1-%5Cfrac%7B%5Calpha%7D%7B2%7D%7D%5Ccdot%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%5B%5D%7Bn%7D%7D%5Crbrack)
Where n is the sample size, and Z is the z-score for 1 - α/2. Using the known values:
![CI(\mu)=\lbrack30.0-Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}},30.0+Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}}\rbrack](https://tex.z-dn.net/?f=CI%28%5Cmu%29%3D%5Clbrack30.0-Z_%7B0.99%7D%5Ccdot%5Cfrac%7B2.40%7D%7B%5Csqrt%5B%5D%7B28%7D%7D%2C30.0%2BZ_%7B0.99%7D%5Ccdot%5Cfrac%7B2.40%7D%7B%5Csqrt%5B%5D%7B28%7D%7D%5Crbrack)
Where (from tables):
Finally, the interval at 98% confidence level is:
Answer:
4½ km
Step-by-step explanation:
2 cm= 1 km
1 cm= ½ km
4cm×2km = 8cm
8 cm (4 km) + 1 cm (½ km) = 9 cm
9 cm/ 4 ½ km
Answer:
b. 30 ft³
Step-by-step explanation:
5 × 8 is the volume of one side.
5 × 8 = 40
40 + 40 + 40 = 120
120 in.³
Answer:
The coordinates are (6.5, 1.7).
Step-by-step explanation:
The difference between A and B's x-coordinate is 15. 7/10 of this is 10.5, which added to -4 gives us an x-coordinate of 6.5.
The difference between A and B's y-coordinate is 11. 7/10 of this is 7.7, which added to -6 gives us a y-coordinate of 1.7.
Therefore, the coordinates are (6.5, 1.7).
