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2 years ago

5

When charles randomly chooses a fruit from a basket of apples and oranges, the odds are 5 to 3 that he will select an orange. wh

at is the probability that he chooses 2 oranges, if fruits are not replaced?

1 answer:

Naily [24]2 years ago

7 0

0 bc 5 to 3 =543 chances 0 unlikely

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Your gross income is<br> $1945.63 of which you<br> get to keep 86% after<br> taxes.

netineya [11]

Answer: You get to keep 1,673.24

You pay 272.38 in taxes.

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2 years ago

PLEASE ANSWER !

ivanzaharov [21]

Answer:I think no, because 25+35+45=150. 150x3=450

Maybe, for 4 months he'd have enough. So, 150x4=600. So Jamal would have some extra money!

Step-by-step explanation:

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3 years ago

Which of the a-values satisfy the following inequality?<br> 7 + a < 11

Zolol [24]

Answer:

a < 4

Step-by-step explanation:

7 + a < 11

Subtract 7 from each side

7+a-7 <11-7

a < 4

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2 years ago

Read 2 more answers

You spin the spinner, flip a coin, then spin the spinner again. Find the probability of the compound event. Write your answer as

Paraphin [41]

Answer:

The probability of not spinning a 5, flipping heads, then spinning a 1 is 0.08

Step-by-step explanation:

I may assume the spin contains 5 numbers ( plz change and recalculate if the no. of numbers is different)

P(not spinning a 5) = 4/5

P(flipping head) = 1/2

P(spinning 1) = 1/5

P(not spinning a 5, flipping heads, then spinning a 1)= 4/5 * 1/2 * 1/5 = 0.08 = 0.1

5 0

2 years ago

We measure the diameters for a random sample of 25 oak trees in a neighbourhood. Diameters of oak trees in the neighbourhood fol

jarptica [38.1K]

Answer:

The required confidence inteval = 94.9%.

Step-by-step explanation:

Confidence interval: Mean ± Margin of error

Given: A confidence interval for the true mean diameter of all oak trees in the neighbourhood is calculated to be (36.191, 42.969).

i.e. Mean + Margin of error = 42.969 (i)

Mean - Margin of error = 36.191 (ii)

Adding (i) and (ii), we get

$2Mean =79.16\\\\\Rightarrow\ Mean= 39.58$

Margin of error = 42.969-39.58 [from (i)]

= 3.389

Margin of error = $t^* \dfrac{\sigma}{\sqrt{n}}$

here n= 25 $, \ \sigma=8.25$

i.e.

$3.389=t^*\dfrac{8.25}{5}\\\\\Rightarrow\ t^* = \dfrac{3.389}{1.65}\\\\\Rightarrow\ t^* =2.0539 \$

Using excel function 1-TDIST.2T(2.054,24)

The required confidence inteval = 94.9%.

7 0

2 years ago