Answer: -2
Step-by-step explanation:
Answer:
0
Step-by-step explanation:
I mean, what expression are you looking?
I dont see anything or a pic to solve :/
The given parallelogram is a rhombus
Solution:
Option A: Rhombus
Let us recall the property of rhombus.
- Diagonals bisect each other at right angles.
- Opposite angles are congruent.
Here diagonals bisect the angles equally each 72°.
Opposite angles are congruent(72° + 72° = 144°).
Hence the given parallelogram is a rhombus.
Option B: Rectangle
Let us recall the property of rectangle.
- Diagonals bisect each other.
- All the angles of a rectangle are 90°.
Here 72° + 72° = 144°, not 90°.
So, the given parallelogram is not a rectangle.
Option C: Square
Let us recall the property of square.
- Diagonals bisect each other.
- All the angles of a square are 90°.
Here 72° + 72° = 144°, not 90°.
So, the given parallelogram is not a square.
