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Sindrei [870]
3 years ago
8

The square root of 5 is between which two integers? Explain your reasoning.

Mathematics
1 answer:
tankabanditka [31]3 years ago
8 0

The square root of 5 is the positive real number that, when multiplied by itself, gives the prime number 5. It is more precisely called the principal square root of 5, to distinguish it from the negative number with the same property





                                         hope it helps


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Find x so that x, X +2, X'+3 are the first three terms of a geometric sequence. Then find the 5" term of the
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Step-by-step explanation:

We know that the first three terms of the geometric sequence is <em>x, x</em> + 2, and <em>x </em>+ 3.

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Then our second term will be our first term multiplied by the common ratio <em>r</em>. So:

x+2=xr

And our third term will be our first term multiplied by the common ratio <em>r</em> twice. Therefore:

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Solve for <em>x</em>. From the second term, we can divide both sides by <em>x: </em>

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Substitute this into the third equation:

\displaystyle x+3=x\Big(\frac{x+2}{x}\Big)^2

Square:

\displaystyle x+3 = x\Big( \frac{(x+2)^2}{x^2} \Big)

Simplify:

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We can multiply both sides by <em>x: </em>

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Isolate the <em>x: </em>

-x=4

Hence, our first term is:

x=-4

Then our common ratio <em>r</em> is:

\displaystyle r=\frac{(-4)+2}{-4}=\frac{-2}{-4}=\frac{1}{2}

So, our first term is -4 and our common ratio is 1/2.

Then our sequence will be -4, -2, -1, -1/2, -1/4.

You can verify that the first three terms indeed follow the pattern of <em>x</em>, <em>x</em> + 2, and <em>x</em> + 3.

So, our fifth term is -1/4.

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