Answer:
The answer are:
•Brenna wants to have a career in computer-related work.
•Cody wants to manage a company's office.
Explanation:
If the answer helps you PLEASE mark my answer as brainliest
Stay Safe,Stay Healthy and Stay Happy
Answer:
5
Explanation:
Word problem.
First statememt
n/2 - 4 = -6. ....... (1)
Second statement.
3n + 7 = x. ....... (2)
From (1)
n/2 - 4 = -6.
n/2 = -6 +4
n/2 = -2
n= -4
Put n into (2).
3n + 7 = x
3(-4) +7 = x
x= -12 +7 = -5
The answer is -5.
It’s m3 lol my keyboard doesn’t have the feature to write it professionally but it’s m3
A black and white scene showing men on horseback and men standing in a field. this print, created by picasso, displays a bold, highly contrasting design, which is characteristic of wood engraving.
Engraving begins by using a sharp, hand-held cutting device called a chisel to draw a design directly onto a metal plate. The tip of the chisel is sharp and pointed. The technique of wood engraving has been used for centuries to reproduce drawings and paintings.
This allowed more people to own or see the artwork of artists who would otherwise only have the original, eliminating the possibility of additional "copies" of their own images. By the 19th century, it was largely abandoned in favor of etching.
Picasso's use of chisels was always unorthodox, but he and other artists used chisels to create sharp, crisp lines on his plates that were etched into the printed image. converted evenly.
The correct answer is option B.
Know more about wood engraving here
brainly.com/question/11252764
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Answer: Twice the previous time would be taken to reach the same speed v with the puck of mass 2m.
Explanation:
Let a Force pushes the hockey puck of mass m.
Then acceleration, a= \frac{F}{m}a=mF
From the equation of motion,
\begin{gathered}\➪ v=u+at\\ v=0+\frac{F}{m}\Delta t\end{gathered}⇒v=u+atv=0+mFΔt ......(1)
In the second case, when mass is 2m, then acceleration,
a'=\frac{F}{2m}a′=2mF
and t' is the time taken.
The final speed is v,
\begin{gathered}\➪ v=0+ a't'\\ \➪ \frac {F}{m}\Delta t=\frac{F}{2m}t'\\ \➪ t'= 2\Delta t\end{gathered}⇒v=0+a′t′⇒mFΔt=2mFt′⇒t′=2Δt using equation (1)
Hence, it would take two times the previous amount of time to push the pluck of double mass.
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