Select the correct answer.

SAT

2 answers:

zloy xaker [14]3 years ago

8 0

Answer: OB

Explanation: Most viruses reproduce in a cycle known as the lyctic cycle. This is when they attatch to the host cell, inject genetic material into the host, takes over the cell's metabolism causing the creation of new proteins and nucleic acids by the host cell's organelles. Then, proteins and nucleic acids are assembled into new viruses. Virus enzymes cause the cell to burst and viruses are released from the host cell. These new viruses can infect other cells.

devlian [24]3 years ago

7 0

Answer:

OB. They infect a healthy cell and use nutrients from that cell to provide energy for asexual reproduction.

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a helicopter flies parallel to the ground at an altitude of 1/2 kilometer and at a speed of 2 kilometers per minute. if the heli

Murrr4er [49]

The Pythagoras' theorem and the uniform motion allows to find the answer for the rate of change of distance is

v = 32.3 m / s

The distance is the length of the segment that a white house wing with the helicopter, this can be found using the Pythagoras' theorem

R = $\sqrt{x^2 + y^2}$

Where R is the distance, x is the horizontal distance where the helicopter flies and y is the vertical distance that corresponds to the flight height

y = 500 m

Since the helicopter flies at constant speed, we can use the uniform motion relation

$v_h$ = $\frac{x}{t}$

x = $v_h$ t

Where $v_h$ is the speed of the helicopter and t is the time

We substitute

r = $\sqrt {(V_h \ t)^2 + y^2}$

Kinematics defines velocity as the change of position in the unit of time

$v = \frac{dR}{dt}$

$v = \frac{1}{2} \ \frac{2 ( v_h t) v_h}{ \sqrt{(v_h t)^2 + y^2} }$

$v = \frac{v_h^2 \ t}{ \sqrt{(v_h t)^2 + y^2} }$

This expression is the change in distance as a function of time for a given speed. In the exercise, this speed is requested for a time of one minute, for the helicopter speed of

v = 2km/min ( $\frac{1000m}{1km}$ ) ( $\frac{1 min}{60s}$ ) = 33.33 m / s