Based on the information given, it has been computed that the activation energy will be 105.8Kj.
<h3>How to calculate activition energy</h3>
From the information given,
T1 = 25 + 273 = 298K
T2 = 35 + 273 = 308J
R = 8.314J/mol
K2/K1 = 4
Therefore,
log(4) = E/(2.303 × 8.314) × [10/(298 × 308)]
= (0.602 × 2.303 × 8.314 × 298 × 308) / 10
= 105.8KJ
Therefore, the activation energy is 105.8KJ.
Learn more about activation energy on:
brainly.com/question/1380484
Answer:
6CO2 + 6H2O → C6H12O6 + 6O2
Explanation:
is the photosynthesis equation
Answer:Solving the quadratic equation, the coordinates of the roots are: (-1,0) and (-3,0)
The quadratic equation given is:
Which has coefficients .
Now, we find the solutions:
The coordinates of the roots are and , as a root is a value of x when y = 0, thus, in the problem, (-1,0) and (-3,0).
A similar problem is given at brainly.com/question/13729358
Explanation:
Answer:
AB = 16 Units
Explanation:
In the given figure, CD is the diameter and AB is the chord of the circle.
Since, diameter of the circle bisects the chord at right angle.
Therefore, AE = 1/2 AB
Or AB = 2AE...(1)
Let the center of the circle be given by O. Join OA.
OA = OD = 10 (Radii of same circle)
Triangle OAE is right triangle.
Now, by Pythagoras theorem:
