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3 years ago

2. Here is a picture of an older version of the flag of Great Britain. There is a rigid

Mathematics

1 answer:

Nitella [24]3 years ago

5 0

Answer:

no.

Step-by-step explanation:

the 4 on the sides are half the area of the ones of the top and bottom because if you take two small ones they will fit with one of the big ones.

sorry if I'm wrong.

You might be interested in

Use the distributive or FOIL method to find the product. (5i + 8)(4i + 6)

balandron [24]

I think you would combine like Terms

3 0

2 years ago

A rectangle is 6yards longer than it is wide. Find the dimensions of the rectangle if it’s area is 187 square yards

emmasim [6.3K]

Answer:

Width = 11 yards

Length = 17 yards

Step-by-step explanation:

First of all, the length of the rectangle is 6 yards longer than the width, this means, length = width + 6 yards. This dimensions can be represented on figure 1, where w is width, and l, for length.

We know the area of a rectangle is A = width x length

For our case 187 = w . (w + 6)

Using the Distributive Property for the multiplication we obtain

$187 = w^{2} +6w$

$w^{2} +6w-187 =0,$

Using the quadratic formula $w=\frac{-b\±\sqrt{b^{2}-4ac } }{2a}$ where a = 1, b = 6, c = - 187 and replacing into the formula, we will have:

$w=\frac{-6\±\sqrt{6^2-4(1)(-187)} }{2(1)}$

$w=\frac{-6\±\sqrt{36+748} }{2}=\frac{-6\±\sqrt{784} }{2}=\frac{-6\±28}{2}$

We have two options: $w=\frac{-6+28}{2}=\frac{22}{2}=11 yards$

$w=\frac{-6-28}{2}=\frac{-34}{2}=-17 yards$ But a distance (width) can not be negative so, this answer for w must be discarded.

The answer must be width = 11 yards.

To find the length $l =\frac{187}{11}=17 yards$

6 0

2 years ago

An economist uses the price of a gallon of milk as a measure of inflation. She finds that the average price is $3.82 per gallon

salantis [7]

Answer:

(a) The standard error of the mean in this experiment is $0.052.

(b) The probability that the sample mean is between $3.78 and $3.86 is 0.5587.

(c) The probability that the difference between the sample mean and the population mean is less than $0.01 is 0.5754.

(d) The likelihood that the sample mean is greater than $3.92 is 0.9726.

Step-by-step explanation:

According to the Central Limit Theorem if we have an unknown population with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from the population with replacement, then the distribution of the sample means will be approximately normally distributed.

Then, the mean of the distribution of sample mean is given by,

$\mu_{\bar x}=\mu$

And the standard deviation of the distribution of sample mean is given by,

$\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}$

The information provided is:

$n=40\\\mu=\$3.82\\\sigma=\$0.33$

As n = 40 > 30, the distribution of sample mean is $\bar X\sim N(3.82,\ 0.052^{2})$ .

(a)

The standard error is the standard deviation of the sampling distribution of sample mean.

Compute the standard deviation of the sampling distribution of sample mean as follows:

$\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}$

$=\frac{0.33}{\sqrt{40}}\\\\=0.052178\\\\\approx 0.052$

Thus, the standard error of the mean in this experiment is $0.052.

(b)

Compute the probability that the sample mean is between $3.78 and $3.86 as follows:

$P(3.78$

$=P(-0.77$

Thus, the probability that the sample mean is between $3.78 and $3.86 is 0.5587.

(c)

If the difference between the sample mean and the population mean is less than $0.01 then:

$\bar X-\mu_{\bar x}$

Compute the value of $P(\bar X$ as follows:

$P(\bar X$

$=P(Z$

Thus, the probability that the difference between the sample mean and the population mean is less than $0.01 is 0.5754.

(d)

Compute the probability that the sample mean is greater than $3.92 as follows:

$P(\bar X>3.92)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}}>\frac{3.92-3.82}{0.052})$

$=P(Z$

Thus, the likelihood that the sample mean is greater than $3.92 is 0.9726.

3 0

3 years ago

1/6+1/2 simplest form

vlada-n [284]

Lowest common denominator-> 6
1/2 multiply both top and bottom by 3 to get it in sixths
1/6+3/6=4/6
4/6 simplifies to 2/3.
2/3 is the simplest form to your question.

7 0

3 years ago

Upon completion of an experiment a student realizes that the technique used for measuring the length and width of a rectangle ha

eduard

Answer:

809.4cm²

Step-by-step explanation:

Given the following :

Systematic error = 3.8cm (The measured length is always more than the actual length.)

Most probable dimension :

Width = 85.7 cm

Length = 123.5 cm

Hence most probable area of Rectangle :

Area = Length × Width

Area = 85.7cm × 123.5cm = 10583.95 cm²

Dimension due to Systematic error :

Length = (85.7cm + 3.8cm) = 89.5cm

Width = (123.5cm + 3.8cm) = 127.3cm

Area = Length × width

Area = ( 89.5cm × 127.3) = 11393.35cm²

Systematic error of the area :

value of area with Systematic error - Probable value of area :

11393.35cm² - 10583.95 cm² = 809.4cm²

6 0

3 years ago