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3 years ago

I need help with number 1 please help

Mathematics

1 answer:

Shalnov [3]3 years ago

3 0

Answer:

D. they are noncollinear

Step-by-step explanation:

this is because they aren't in one straight line going x, y, z, w. because they intersect and make cross shape.

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Please help me it’s very important, give a correct explanation

AlekseyPX

Step-by-step explanation:

triangle MAC=triangle MBD=90 Degree

Therefore, From right angled triangle

AC=BD

8 0

3 years ago

Is 7 a solution of 5x - 3 = 12?

V125BC [204]

Answer:

Step-by-step explanation:

5x - 3 = 12

5x=12+3

x=15/5=3

x=3

substitute x with 7 to find if it is a solution :

5(7)-3=12

35-3 ≠12 ( so no 7 is not a solution)

3 0

3 years ago

In 2013, the moose population in a park was measured to be 5,100. By 2018, the population was measured again to be 5,200. If the

natka813 [3]

Answer:

$P(t) = 5100e^{0.0039t}$

Step-by-step explanation:

The exponential model for the population in t years after 2013 is given by:

$P(t) = P(0)e^{rt}$

In which P(0) is the population in 2013 and r is the growth rate.

In 2013, the moose population in a park was measured to be 5,100

This means that $P(0) = 5100$

$P(t) = 5100e^{rt}$

By 2018, the population was measured again to be 5,200.

2018 is 2018-2013 = 5 years after 2013.

So this means that $P(5) = 5200$ .

We use this to find r.

$P(t) = 5100e^{rt}$

$5200 = 5100e^{5r}$

$e^{5r} = \frac{52}{51}$

$\ln{e^{5r}} = \ln{\frac{52}{51}}$

$5r = \ln{\frac{52}{51}}$

$r = \frac{\ln{\frac{52}{51}}}{5}$

$r = 0.0039$

So the equation for the moose population is:

$P(t) = 5100e^{0.0039t}$

5 0

3 years ago

Write the expression as a square of a binomial if possible: 19x^2+2/15xy+1/25y^2 Anyone who answers my question I will name brai

ZanzabumX [31]

Answer:

Formula: a² + 2ab + b² = (a + b)²

The square root of 1/9x² = 1/3x so a = 1/3x and b = 1/5y.

The answer is (1/3x + 1/5y)².

3 0

4 years ago

PLEASE HELP , TRYING TO BE ON HONOR ROLL !

borishaifa [10]

Option A

The solution is $(0, \frac{-1}{4})$

Solution:

Given system of equations are:

3x + 6y = 1 ------ eqn 1

x - 4y = 1 ------ eqn 2

We have to find solution to system of equations

We can use substitution method

From eqn 2,

x = 1 + 4y -------- eqn 3

Substitute eqn 3 in eqn 1

3(1 + 4y) + 6y = 1

3 + 12y + 6y = 1

18y = 1 - 3

18y = -2

Divide both sides by 18

$y = \frac{-2}{18}\\\\y = \frac{-1}{4}$

Substitute the above value of y in eqn 3

$x = 1 + 4 \times \frac{-1}{4}\\\\x = 1-1\\\\x = 0$

Thus solution is $(0, \frac{-1}{4})$

8 0

3 years ago