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3 years ago

Can someone please help me with this question ?

Mathematics

1 answer:

____ [38]3 years ago

5 0

The cost of water would be $615 as he needs 3 acre-feet of water for 205 acre/ft

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14 less than 8 times a number is 3 more than 4 times the number. What is the number?

e-lub [12.9K]

Answer:

x = 17/4

Step-by-step explanation:

Let x = the number

8x-14 = 4x+3

Subtract 4x from each side

8x -14-4x = 4x+3-4x

4x-14 = 3

Add 14 to each side

4x-14+14 = 3+14

4x = 17

Divide by 4

4x/4 = 17/4

x = 17/4

8 0

3 years ago

Write an equation of the line that passes through (18, 2) and is parallel to the line 3y−x=−12

Stolb23 [73]

Answer:

y= -4x+74

Step-by-step explanation:

hope that helped

5 0

3 years ago

Read 2 more answers

Find area, round to nearest tenth

Gnom [1K]

Answer:

160 in²

Step-by-step explanation:

The formula for the area of a triangle is ...

A = 1/2bh . . . . base length b, height h

Here, the triangle has a base length of 32 in, and a height of 10 in. Its area is ...

A = 1/2(32 in)(10 in) = 160 in²

3 0

2 years ago

Which is the graph of y – 3 = (x + 6)?

velikii [3]

The Answer is A (The first graph in the photo), I attached the graph to help you see the answer for y-3=- $\frac{2}{3}$ (x+6).

I hope you have a good day and please give me brainest if that is correct!

3 0

3 years ago

Sadiq measured the dimensions of a 1 kg bag of sugar and found the length was 9.2 cm, the width was 6 cm and the height was 14.1

garik1379 [7]

Answer:

$d=1.28\times 10^{-6}\ g/cm^3$

Step-by-step explanation:

The mass of a bag of sugar, m = 1 kg = 0.001 g

Length of bag, l = 9.2 cm

Width of bag, b = 6 cm

Height of the bag, h = 14.1 cm

We need to find the density of the sugar bag.

Density = mass/volume

So,

$d=\dfrac{0.001\ g}{9.2\times 6\times 14.1\ cm^3}\\\\d=1.28\times 10^{-6}\ g/cm^3$

So, the density of the bag is $1.28\times 10^{-6}\ g/cm^3$ .

7 0

3 years ago