(x-8) ^ 2 = 121
(x-8) = + / - root (121)
x = 8 +/- root (121)
The solutions are:
x1 = 8 + root (121)
x2 = 8 - root (121)
2a ^ 2 = 8a-6
2a ^ 2-8a + 6 = 0
a ^ 2-4a + 3 = 0
(a-1) (a-3) = 0
The solutions are:
a1 = 1
a2 = 3
x ^ 2 + 12x + 36 = 4
x ^ 2 + 12x + 36-4 = 0
x ^ 2 + 12x + 32 = 0
(x + 4) (x + 8) = 0
The solutions are:
x1 = -8
x2 = -4
x ^ 2-x + 30 = 0
x = (- b +/- root (b ^ 2 - 4 * a * c)) / 2 * a
x = (- (- 1) +/- root ((- 1) ^ 2 - 4 * (1) * (30))) / 2 * (1)
x = (1 +/- root (1 - 120))) / 2
x = (1 +/- root (-119))) / 2
x = (1 +/- root (119) * i)) / 2
The solutions are:
x1 = (1 + root (119) * i)) / 2
x2 = (1 - root (119) * i)) / 2
STEP BY STEP EXPLANATION
(Mark brainliest pls)
Square root is 2 square + 4 square + 1 because 1 does not enable a square perhaps for negatives to be imputed, and we know 2 square will be 1 hence,
1 x 1 = 1 squared
2 x 2 = 4 squared
Perhaps for 1, you will have to use a formula equation and add tang maybe. Etc I don’t know if tang but u will also have to convert 1 to a decimal to find the square root of 1, 1 is an odd number so it will end up with remainder decimals or just do 1x1, etc.
Hence u
(2 square + 4 square) + 1square?
It depends on addition or order of operations subtraction addition or you will might use multiply
if the subject is about multiply or Division so try and do it because i don’t know if I’m right
..
REMEMBER
PEMDAS
Please Excuse My Dear Aunt Sally
Parentheses
Equations
Multiplication
Division
Addition
Subtraction
ORDER OF OPERATIONS.
try and solve it hope this helps!
Have a nice day
Your answer is: 20
They have 4 different backgrounds and 5 different poses which means you just have to multiply the 4 backgrounds*the 5 different poses to discover how many different pictures you could have at the most.
hope this helps!
Answer: zxy=39 wxy=78
Step-by-step explanation:
Since xz bisects wxy, the 2 angles that make up wxy are equal.
