If the ball has an initial velocity of 130 ft/s and an angle of 41°, the time it will take the ball to hit the ground is 5.33 seconds
Since the ball is a projectile, we need to find its time of flight for it to reach the ground
<h3>Time of flight of ball</h3>
The time of flight of the ball is the time it will take to hit the ground. It is given by
T = 2UsinФ/g where
- U = speed of ball = 130 ft/s
- Ф = angle of projection = 41° and
- g = acceleration due to garvity = 32 ft/s²
Substituting the values of the variables into the equation, we have
T = 2UsinФ/g
T = 2 × 130 ft/s × sin41° ÷ 32 ft/s²
T = 260 ft/s × 0.6561 ÷ 32 ft/s²
T = 170.58 ft/s ÷ 32 ft/s²
T = 5.33 seconds
So, the time it will take the ball to hit the ground is 5.33 seconds
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Answer:30
Step-by-step explanation:
Answer:
4n^2-20n+25
Step-by-step explanation:
(-2n+5)^2
=4n^2-20n+25
The variables are the letters g and h because, t<span>he coefficient is the number in front of the variables (the letters are variables)</span>
Answer:
392939939393939399393939393
Step-by-step explanation:
