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zheka24 [161]
3 years ago
6

What is the lateral area of a regular square pyramid if the base edges are of length 24 and perpendicular height is 5?

Mathematics
1 answer:
iren2701 [21]3 years ago
4 0

Answer:

The lateral area is 624 unit²

Step-by-step explanation:

* Lets explain how to solve the problem

- The regular square pyramid has a square base and four congruent

 triangles

- The slant height of it = \sqrt{(\frac{1}{2}b)^{2}+h^{2}}, where

  b is the length of its base and h is the perpendicular height

- Its lateral area = \frac{1}{2}.p.l, p is the perimeter of the base

 and l is the slant height

* Lets solve the problem

∵ The base of the pyramid is a square with side length 24 units

∵ Its perpendicular height is 5 units

∵ The slant height (l) = \sqrt{(\frac{1}{2}b)^{2}+h^{2}}

∴ l = The slant height of it = \sqrt{(\frac{1}{2}.24)^{2}+5^{2}}

∴ l = \sqrt{(12)^{2}+25}=\sqrt{144+25}=\sqrt{169}=13

∴ l = 13 units

∵ Perimeter of the square = b × 4

∴ The perimeter of the base (p) = 24 × 4 = 96 units

∵ The lateral area = \frac{1}{2}.p.l

∴ The lateral area = \frac{1}{2}.(96).(13)

∴ The lateral area = 624 unit²

* The lateral area is 624 unit²

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Step-by-step explanation:

We are given that,

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Since, we know,

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Solve question 10 using substitution or elimination. Show all work.
BlackZzzverrR [31]
Solid paper costs 1.75 each
Printed paper costs 2.50 each

Given:
Ben = $43.50 (12 rolls solid paper and 9 rolls of
printed paper)
Joel = $51.50 (8 rolls solid paper and 15 rolls of
printed paper)
Let x = solid paper
Let y= printed paper
12x + 9y = 43.50
8x + 15y = 51.50

Find X:
8x + 15y = 51.50
8x = 51.50 - 15y
x= (51.50 - 15y)8

Substitute X:
12x + 9y = 43.50
12(51.50 - 15y)/8 + 9y = 43.50
(618 - 180y)/8 + 9y = 43.50
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Y= 2.50

x = (51.50 - 15y)/8
x = (51.50 - 15(2.5) /8
x= (51.50 - 37.50\8
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X = 1.75

To check: x = 1.75; y = 2.5
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8(1.75) + 15(2.5) = 51.50
14 + 37.50 = 51.50
51.50 = 51.50

Hope that helps! Have a good day :)
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