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zheka24 [161]
3 years ago
6

What is the lateral area of a regular square pyramid if the base edges are of length 24 and perpendicular height is 5?

Mathematics
1 answer:
iren2701 [21]3 years ago
4 0

Answer:

The lateral area is 624 unit²

Step-by-step explanation:

* Lets explain how to solve the problem

- The regular square pyramid has a square base and four congruent

 triangles

- The slant height of it = \sqrt{(\frac{1}{2}b)^{2}+h^{2}}, where

  b is the length of its base and h is the perpendicular height

- Its lateral area = \frac{1}{2}.p.l, p is the perimeter of the base

 and l is the slant height

* Lets solve the problem

∵ The base of the pyramid is a square with side length 24 units

∵ Its perpendicular height is 5 units

∵ The slant height (l) = \sqrt{(\frac{1}{2}b)^{2}+h^{2}}

∴ l = The slant height of it = \sqrt{(\frac{1}{2}.24)^{2}+5^{2}}

∴ l = \sqrt{(12)^{2}+25}=\sqrt{144+25}=\sqrt{169}=13

∴ l = 13 units

∵ Perimeter of the square = b × 4

∴ The perimeter of the base (p) = 24 × 4 = 96 units

∵ The lateral area = \frac{1}{2}.p.l

∴ The lateral area = \frac{1}{2}.(96).(13)

∴ The lateral area = 624 unit²

* The lateral area is 624 unit²

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Answer:

No, Angela is not correct.

As the method Jim was performing will also lead to the solution.

Step-by-step explanation:

We are given first equation as:

                  Ax + By = C

Second equation is:

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Jim solved the equation as:

He begins by multiplying equation (1) by D and equation (2) by A.

and so by subtracting both the equations he will obtain a value of y.

and then put the y-value in any of the given two equations to obtain the value of x.

Angela Method:

you should have multiplied equation (1) by E and equation (2) by B.

and when she will subtract both the equations she will get the value of x first and then when she will put the value of x in any of the given equation she will obtain the value of y.

But both will get a value for x and y.

Hence, the method Jim was performing was also correct.

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Read 2 more answers
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